sort which is default compare function

[artev]

in the default sort which is the compare function used?
alphabetical ordination is so:arry.sort();
but which is the default function used?

is there a good link wich example for alphabetical order
and also for multiarray order? (previous post)


which it is the difference between:
function compareNumbers( a, b)
{return a - b;}
and this:
function compare(a, b)
{ if (a < b by) return -1;
else if (a than b ) return 1;
else return 0;
}

[Evertjan.]

artev wrote on 26 mei 2007 in comp.lang.javas cript:

which it is the difference between:

function compareNumbers( a, b)
{return a - b;}

and this:

function compare(a, b)
{ if (a < b by) return -1;

if (a < b)

else if (a than b ) return 1;

else if (a b )

else return 0;
}

No difference when used in a numeric .sort(),
as .sort() only looks for positive, zero or negative.

The first sort function should be faster,
especially important with a large array.

The second one also works in a string compare sort.

In the second function the else-es are not neccessary:

function compare(a, b) {
if (a<b) return -1;
if (a>b) return 1;
return 0;
};
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[artev]

in my previous I have now post a new code that not work
good;
you know where is the problem?

[Evertjan.]

artev wrote on 26 mei 2007 in comp.lang.javas cript:

in my previous I have now post a new code that not work
good;
you know where is the problem?

What and to whom are you talking [about]?

[please always quote on usenet]

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)