null if evaluation

[Bryce Maschino]

hello,
i'm working on a project searching through a list of arrays based on
user input. the problem is that if a user does not define a certain
variable, my if statement will not evaluate. i need a way to tell the
if statement to skip over a certain evaluation if the value is null.

if ((House[i][1] == beds) && (House[i][2] == baths)) {
statments
}

if someone doesn't define # of beds, how do i skip that evaluation?
thanks!

bryce

[Nathan Zumwalt]

It sounds like you're running into problems because you're not using
good OO design. Instead of using a two dimensional array, you should
use an array of House objects:

public class House {
private int numberBeds;
private int numberBaths;

public House(int numberBeds, int numberBaths) {
this.numberBeds = numberBeds;
this.numberBaths = numberBaths;
}
public int getNumberBeds() { return numberBeds; }
public int getNumberBaths() { return numberBaths; }
}

Then, you wouldn't have to worry about the second dimension of your
array being defined or not:

//Assume houseArray is of type House
if ( houseArray[i].getNumberBeds == beds &&
houseArray[i].getNumberBaths == baths ) {
//Do stuff here.
}

Hope this helps.

//Nathan

ho***********@hotmail.com (Bryce Maschino) wrote in message news:<3b*************************@posting.google.c om>...

hello,
i'm working on a project searching through a list of arrays based on
user input. the problem is that if a user does not define a certain
variable, my if statement will not evaluate. i need a way to tell the
if statement to skip over a certain evaluation if the value is null.

if ((House[i][1] == beds) && (House[i][2] == baths)) {
statments
}

if someone doesn't define # of beds, how do i skip that evaluation?
thanks!

bryce

[Takeda]

Bryce,

I agree Nathan, but maybe you can not do it now (a good OO design
must be done at beginning). So, you can "to fix" your code, trying it:

if ( (House[i][1] != null) && (House[i][1] == beds) && (House[i][2] ==
baths)) {
statments
}
It works because shortcut conditional (it means the expression will
not be checked until end. The JVM verifies the conditions, one by one
(left to right), until the expression becomes false (with AND
operator) or true (with OR operator).
The same thing if you wanna check baths.
But, remember what Nathan told about OO design...
na*****@hotmail.com (Nathan Zumwalt) wrote in message news:<52**************************@posting.google. com>...

It sounds like you're running into problems because you're not using
good OO design. Instead of using a two dimensional array, you should
use an array of House objects:

public class House {
private int numberBeds;
private int numberBaths;

public House(int numberBeds, int numberBaths) {
this.numberBeds = numberBeds;
this.numberBaths = numberBaths;
}
public int getNumberBeds() { return numberBeds; }
public int getNumberBaths() { return numberBaths; }
}

Then, you wouldn't have to worry about the second dimension of your
array being defined or not:

//Assume houseArray is of type House
if ( houseArray[i].getNumberBeds == beds &&
houseArray[i].getNumberBaths == baths ) {
//Do stuff here.
}

Hope this helps.

//Nathan

ho***********@hotmail.com (Bryce Maschino) wrote in message news:<3b*************************@posting.google.c om>...

hello,
i'm working on a project searching through a list of arrays based on
user input. the problem is that if a user does not define a certain
variable, my if statement will not evaluate. i need a way to tell the
if statement to skip over a certain evaluation if the value is null.

if ((House[i][1] == beds) && (House[i][2] == baths)) {
statments
}

if someone doesn't define # of beds, how do i skip that evaluation?
thanks!

bryce