Need help with a method exception!

[Sekm]

Hi there i want a basic menu which the user inputs a number to chose from the menu. Thing is that i need to make sure that the input IS an integer. So i have an InputMismatchEx ception catch but when it occurs, the program just keeps outputting the menu over and over??

 static Scanner sc = new Scanner(System.in);
 
  public static void menu (){
    System.out.println("Please enter a number to select from the following:\n\t1. Create new Array\n\t2. Load array from MyObject.dat");
    int choice = 0;
    try{ 
      choice = sc.nextInt();
      switch(choice){ 
        case 1:
          start();
          break;
        case 2:
          loadArray();
          break;
        default :
          System.out.println("invalid");
      }
    }catch (InputMismatchException e){
      System.out.println("Please enter a valid NUMBER from the menu... Resetting menu.");
    }
    menu();
  }

[JosAH]

Suppose you make your scanner read a nextInt(). If there isn't an int in the input
the scanner doesn't read anything and throws an exception as you have noticed.
If you immediately make it read another nextInt() the scanner sees the same
input and the story repeats itself (i.e. nothing read and an exception thrown) etc.

Simply skip the line that doesn't contain an integer and caused an exception
to be thrown.

kind regards,

Jos

[hsn]

so read it as a string, make sure it is not a char then convert it to integer by using the parse function......

good luck

hsn