Help with my array/ search function

[Gigabyte1]

#include <stdio.h>
#include <stdlib.h>
 
int main(int argc, char *argv[])
   {
/*Array Values*/
        int arnSalaries[10][2] = {21, 10000, 22, 15600, 23, 10000, 24, 56000,
                                           25, 13250, 26, 24750, 27, 18750, 28, 56250,
                                           29, 22450, 30, 27500};
    int nRow, nCol;
    int nEmSal;
    char cFound = 'N';
 
          printf("\nSearching a 2D array\n");
 
/*How to Display the Array*/
      for(nRow = 0; nRow < 10; nRow++)
   {
         printf("%4d %6d\n",arnSalaries[nRow][0], arnSalaries[nRow][1]);
   }
         printf("\n\n");
 
         printf("Please enter the salary : ");
         scanf("%d", &nEmSal);
 
 
 
    funcSearch (arnSalaries, nEmSal);
 
    system("PAUSE");    
    return 0;
   }
/*Search Function*/
int funcSearch(int arnSalaries[10][2],int nEmSal)
   {
    int nRow, nCol;
    char cFound = 'N';
 
     for(nRow = 0; nRow < 10; nRow++)
   {
     if(nEmSal == arnSalaries[nRow][1])
   {
        printf("\nEmployee(s) Found : %d \n", arnSalaries[nRow][0]);
         cFound = 'Y';
        nRow = 10; /* This is to break out of the loop */
   }
   }
 
     if(cFound == 'N')
   {
        printf("Sorry, No Employee(s) Found - Please Try Again\n");
   }
   }

So i wrote this code... However if i type a salary for example 10000 where there's two or more employee who has that salary only 1 result would appear.
What do i do?

[weaknessforcats]

This function:

int funcSearch(int arnSalaries[10][2],int nEmSal)
{etc...

has arguments that are a pointer to an array of 2 int and a second argument for the search salary.

The function is supposed to return an int but i don't see a return of any kind in the code. In any case, the function should return a pointer to an int:

int*   funcSearch(int arnSalaries[10][2],int nEmSal);
 

The pointer returned is the pointer to the int pair that has the nEmSal. The function should return 0 if the salary is not found.

All displays should be in main(). The search function should just search.

In addition, to need to pass in the number of elements. You should not have to hard code a 10 in the function since this locks the function to an array of 10 making it useless for an array of 20. There should be no hard-coded constants in your code.

int* funcSearch(int arnSalaries[10][2],int num elements, int nEmSal)
{etc...

Hint:

int arr[10][2];
 
int (*p)[2] = arr;
 
int x = (arr+9) - (arr+3);

When working with arrays, the name of the array is the address of element 0. So arr is &arr[0]. arr+9 is &arr[9].
Therefore, x is set to 6. The array has 10 elements so the last element has the address of arr+9. Therefore, if the search function ever tries to search arr+10, you have gone off the end of the array and the function should return 0 for the int* meaning "not found".

Consider using an argument that is a pointer to an array of 2 int instead of the number of elements and let the function search up to that address:

int* funcSearch(int arnSalaries[10][2], int end[][2] , int nEmSal)
{etc...

Then you can search this way:

funcSearch(arnSalaries, arnSalaries +10 , int nEmSal)
{etc...

to search from element 0 to element 9. Now you can search any section of the array you wish by correctly setting the call arguments.