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answer of sum comes up short

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  1.     j = M;
  2.     do
  3.     {
  4.         i = 0;
  5.         do
  6.         {
  7.             sum5 = sum5 + array[i][j];
  8.             i++;
  9.         }while(i < N);
  10.         j++;
  11.     }while(j == M);
  12.  
So, M and N are both defined at 5. This piece of code is meant to add together a row from an array declared before, but fails to get the answer right.
The answer is 22 + 62 + 54 + 25 + 48 = 211, yet this program calculates it to 168. Below is the array declared before, the do... while cycles are the same for the other four lines, yet this one comes up short.


{
{98, 14, 99, 49, 22},
{89, 64, 84, 73, 62},
{97, 56, 37, 97, 54},
{84, 32, 93, 15, 25},
{85, 50, 58, 18, 48}
};
Nov 30 '13 #1
1 1109
weaknessforcats
9,208 Recognized Expert Moderator Expert
There are bugs in the code.

j is 5.

The first loop is entered with j of 5 and i of 0. Then element sum[0][5] is accessed. This is outside the array so results are indeterminate.

After the first loop j, which is still 5 is incremented so it's now 6. The outer loop won't exit until j equals M and 6 will never equal 5. This looks like an infinite loop.
Nov 30 '13 #2

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