what is the result of a[++i] = i ; ?

[mxy0226]

if a[3]={-1,-2,-3};
i=0;
what a[++i] = i work?

[vijay6]

Hey mxy0226,

The value of 'i' (1 - One) will assign to a[1].

Workflow:

1) This statement evaluate from right to left.

2) In the right hand side, no changes. The value of 'i' remain as it is (i=0).

3) In the left hand side, first '++i' statement will execute. i.e., The value of 'i' incremented by 1. Now 'i' is 1.

4) Finally the assignment statement execute. a[1] = 1 (Because now 'i' value is 1).

5) After that statement (a[++i] = i) the array 'a' will look like this a[3] = {-1, 1, -3};

[VanessaMeacham]

HI ! this operator perform right to left so vijay6's answer is right. it also overloads.

[Banfa]

Actually the behaviour is undefined because you are accessing a variable (i) more than once between sequence points where one of those accesses modifies the value of the variable.

You do not know what order the 2 sub-expressions of the = operator are evaluated in, it is not specified in the standard.