Type Cast Pointer, Child and Parent Interaction

[hinomotoblade]

Hello there, until now i am still confused about this one, i mean what for we cast the child class to parent class?.. since child class can access all of the member of the parent class, yeah since its has public modifier..

And also, we can cast the parent as a child using dynamic_cast right?.. but what for?..

I still relly confused about pointer interaction, why we need access the pointer thingy..

Thx very much, very very appreciate a little help.. thx thx a lot, already read so many article but still confused.. :)

[weaknessforcats]

In C++ you are not supposed to cast at all.

The cast syntax is there for emergency use. Generally, any cast in a C++ program means you are calling C functions with void* arguments.

For a beginner, any cast in your program means your design is faulty.

Certainly, the type cast of child to parent is almost akways an error. Where did you hear to do that?

As to dynamic_cast, if you can't tell me what it is, then don't use it.

[hinomotoblade]

thanks a lot for replying.. :)

yeah, i just often saw scripts. And several ppl said the reason that for getting the pointer, they just always said, to get address diadadiada, but i think as far as i know, i never use type cast for classes thingy..

For example, the simple one about getting pointer is, making new object from other class, there are 2 way right? using new, and not..
and to access the member is different too, with pointer we use "->", and the other just use ".".. but i think they have same value right..

Thx a lot.. :)

[weaknessforcats]

When you create an object as a local variable you have to know at compile time that you need to create it. But what if you don't? What if the user has to answer a question at run time to determine what kind of object to create? That's where the new operator comes in. This allows you to create an object at run-time and the new operator returns the address of the object. You keep this address in your pointer variable.

C++ provides the "->" operator when useing a pointer to the object and the "." syntax when working with the object directly.

[hinomotoblade]

Ohhhhh thx a lot dude !!.. :D