when i am running the C prog after compile, it is not showing the result.

[nandish ptl]

#include <stdio.h>

void main()
{
int a;
printf("Enter value of a = ");
scanf("%d\n",&a);
a = a + 10;
printf("The final value of a is %d",a);
}

when i am running this simple program it stops showing result. It executes only upto 'scanf'... After entering the 'a' value it is not showing the final result value.(i.e. 56, if a is entered 46) and i have to stop it forcefully from 'windows task manager'.

why it does happen and what is the solution?

Thank you.

[weaknessforcats]

It probably does show your result. However, since you have no code to pause the program after the printf, your result is displayed for only a split-second.

[donbock]

It is common for stdout to be a buffered output. This means that characters written to stdout are held in an internal buffer until either a newline is written to stdout or fflush is called.

Terminate your format string with a newline.

[nandish ptl]

how can i pause the program to display result..?

i tried with different simple codes but the problem remains same. For exmple
i wrote the following code...

#include <stdio.h>

void main()
{
int i,j;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",i);
}
printf("\n");
}
}

when i am running the code black screen appear for a moment and angain main (blue) screen appears..

what is the solution?

Thank you

[nandish ptl]

i terminated the format string with new line.. but it didnt work.

[AdrianH]

the simplest way is:

printf("Press enter to continue...");
fflush(stdout);
scanf("%*s");