number of elemnts in an array

[Arepi]

Hi,

I have function which return whit en double* array.
I tried this to get the size :

double  array[100];
 
double* Function()
    {
           // some code
           return array;
        }
 
int main(int argc, char *argv[])
    {
           double *getarray = Function();
           int  size = sizeof(getarray) / sizeof(getarray[0]);
        }

If I print out the "getarray" variable it give some data, but the value of "size" is 0.
Can anyone explain what's wrong?

Thanks

Arepi

[YarrOfDoom]

You're dividing the size of a pointer (so probably 1 byte as result) by the size of an element of the array (which is a double, and therefore more than one byte). The result of this would be less than zero, but since it's saved in a variable of the type int, that number is rounded down to zero.
As far as I know, the most common solution to this problem is to pass the length of the array along with the array itself.