default template arguments...

[Chris Thomasson]

Is the following use of default template arguments Kosher?
__________________________________________________ _____________
template<
typename T,
void (T::*T_fp_start) () = &T::start,
void (T::*T_fp_join) () = &T::join

struct active {

T object;

struct guard {
T& object;

guard(T& _object) : object(_object) {
(object.*T_fp_start)();
}

~guard() {
(object.*T_fp_join)();
}
};

active() {
(object.*T_fp_start)();
}

~active() {
(object.*T_fp_join)();
}
};

__________________________________________________ _____________

Basically, I want to allow objects which have a common interface of
`T::start()/join()' to be able to use the template above like:

active<objecto;


However, if an object has a custom function it wants to use instead of start
and/or join, it could do something like:
active<object, &object::spawno;
-or-
active<object, &object::spawn, &object::waito;


Is that okay? I am not a C++ expert. However, it seems to compile on GCC and
Comeau...

;^)


--
Chris M. Thomasson
http://appcore.home.comcast.net