Is there a Windows or C++ library function to break down a Filepath?

[Ramon F Herrera]

My application receives a filepath as an argument. Obviously, it can
come in several formats, such as:

filename.ext

..\filename.ext

...\..\filename.ext

this\is_a\relative\path\finally.ext

C:\fully\qualified\path\filename.ext

....and so on.

In Unix there is a function which will do the right thing in every
case, splitting the path into a base and a filename.

Is there such thing, something equivalent in Windows programming?

TIA,

-Ramon

[Ramon F Herrera]

On Oct 22, 1:38 am, "Alf P. Steinbach" <[e-mail]:

* Ramon F Herrera:

My application receives a filepath as an argument. Obviously, it can
come in several formats, such as:

filename.ext

.\filename.ext

..\..\filename.ext

this\is_a\relative\path\finally.ext

C:\fully\qualified\path\filename.ext

...and so on.

In Unix there is a function which will do the right thing in every
case, splitting the path into a base and a filename.

Is there such thing, something equivalent in Windows programming?

Windows programming is off-topic in clc++.

Check out the Boost library's general file handling.

Ooops, I went trigger happy, shot from the hip and didn't even realize
you actually gave some useful info, Alf.

Thanks!

For the record: I am not too fond of the Windows crowd, their ways and
means, and have tried my best to stay on the side of standards,
interoperability (i.e., non-Microsoft), IETF, OSS, etc.

-Ramon

[Andrew]

On Oct 22, 8:32 am, Ramon F Herrera <[e-mail]:

My application receives a filepath as an argument. Obviously, it can
come in several formats, such as:

filename.ext

.\filename.ext

..\..\filename.ext

this\is_a\relative\path\finally.ext

C:\fully\qualified\path\filename.ext

...and so on.

In Unix there is a function which will do the right thing in every
case, splitting the path into a base and a filename.

Is there such thing, something equivalent in Windows programming?

TIA,

-Ramon

Look to the Shell Path functions in MSDN.
One of them is PathFindFileName which takes a path and returns the
filename

[jtorjo2007]

On 22 Oct, 08:32, Ramon F Herrera <[e-mail]:

My application receives a filepath as an argument. Obviously, it can
come in several formats

Why don't you use boost::filesystem library? It's cross-platform.
Best
John

--
http://John.Torjo.com -- C++ expert
.... call me only if you want things done right