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pointers to Enum in C

63 New Member
Expand|Select|Wrap|Line Numbers
  1. #include <string.h>
  2. enum State {yes=1, no=0}SS, *ptr;
  3. struct Example {
  4. enum State *ptr;
  5. }EX;
  6.  
  7. enum State SS=yes;
  8. main()
  9. {
  10. struct Example* PTR;
  11. //enum State *ptr;
  12. PTR=&EX;
  13. ptr=&SS;
  14. printf("%d",PTR->ptr);
  15. }
  16.  
no errors ....but unable to print the enum values for "yes" and "no"
Is the logic incorect
Sep 20 '07 #1
4 14201
arnaudk
424 Contributor
You've written 'enum' a few too many times; you only need it once to declare a new variable type:
Expand|Select|Wrap|Line Numbers
  1. #include <string.h>
  2. enum State {yes=1, no=0} SS, *ptr;
  3. // Now State type is declared
  4. struct Example {
  5.  State *ptr;
  6.  // ptr is a pointer to a State
  7.  } EX;
  8. State SS=yes;
  9. // SS is a variable of type State
  10.  
[EDIT: Actually, this applies only to C++, not C as you have indicated. Ignore this post]
Sep 20 '07 #2
arnaudk
424 Contributor
Isn't it just that you should write PTR->ptr=&SS; on line 13?
Sep 20 '07 #3
askcq
63 New Member
no its not working
pls help
Sep 21 '07 #4
weaknessforcats
9,208 Recognized Expert Moderator Expert
Avoid defining multiple things on one line. Separate the emum from the variables:
Expand|Select|Wrap|Line Numbers
  1. enum State {yes=1, no=0};
  2. State SS = yes;
  3. State*ptr;
  4.  
Next, when you create yout struct variable, you never initialize the pointer in the variable:
That is, EX.ptr is never pointed at a State variable.

Try this out and let me know what happens.
Sep 21 '07 #5

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