'function' : cannot be explicitly specialized error

[Aarti]

Say I have a class template as follows

template<typename T>
class foo
{
public:
void test();
};

template<typename T>
void foo<T>::test()
{
// function implementation
}

Now if i want to specialize it for say strings, I would do it as
follows
template<>
class foo<string>
{
public:
void test();
};

template<//Gives a error "function cannot be specialized"
void foo<string>::test()
{
// function implementation
}

My question is why do I need to omit the "template<" for functions
of specialized template class? I am trying this with Visual C++
Express 2005 edition.

[Robert Bauck Hamar]

Aarti wrote:

Say I have a class template as follows

template<typename T>
class foo
{
public:
void test();
};

template<typename T>
void foo<T>::test()
{
// function implementation
}

Now if i want to specialize it for say strings, I would do it as
follows
template<>
class foo<string>
{
public:
void test();
};

template<//Gives a error "function cannot be specialized"
void foo<string>::test()
{
// function implementation
}

My question is why do I need to omit the "template<" for functions
of specialized template class? I am trying this with Visual C++
Express 2005 edition.

Because the standard says so. Note that foo<string>::test (assuming string
is a type) is not a template. It is an ordinary member function of the
specialised template foo.

--
rbh

[Aarti]

On Jul 11, 4:47 am, Robert Bauck Hamar <[e-mail]>
wrote:

Aarti wrote:

Say I have a class template as follows

template<typename T>
class foo
{
public:
void test();
};

template<typename T>
void foo<T>::test()
{
// function implementation
}

Now if i want to specialize it for say strings, I would do it as
follows
template<>
class foo<string>
{
public:
void test();
};

template<//Gives a error "function cannot be specialized"
void foo<string>::test()
{
// function implementation
}

My question is why do I need to omit the "template<" for functions
of specialized template class? I am trying this with Visual C++
Express 2005 edition.

Because the standard says so. Note that foo<string>::test (assuming string
is a type) is not a template. It is an ordinary member function of the
specialised template foo.

--
rbh- Hide quoted text -

- Show quoted text -

Ok Got it. Thanks!!!