Casting Pointers in C - Urgent

[Thanks For Help]

I need to get this right ....

suppose I have an array :char p[MAX] //MAX a defined number

we also have a defined structure header,
struct header {...
...}

having the following code

struct header *h;
h = (struct header *) p;

how would this really be reflected in memory;

h and p will be pointing to the same area of memory ?

we can still use p as pointer to the array...

just tell me how are the pointers and the refernced object are affected by casting
??

[Meetee]

h and p will be pointing to the same area of memory ?

Yes, both h and p are pointing to the same area of memory.
You can check it by this way

#include <stdio.h>
struct header
{
//int i = 5;
}*h;
int main()
{
char p[10]={'a','b','c'};
struct header *h;
h = (struct header *) p;
printf("%u\n",h);
printf("%u\n",p);
printf("%s\n",*h);
printf("%c\n",p[2]);
return 0;
}
 

we can still use p as pointer to the array...

Yes :))

Regards

[weaknessforcats]

This code:

char p[10]={'a','b','c'};
struct header *h;
h = (struct header *) p;

will cause you trouble. The array p points to three chars in memory. That's three bytes.

An h* is a pointer to a struct with an int as a member. That typecast is you lying to the compiler about what is really in memory. In this case the cast says an int (4 bytes).

Now when you use h you will corrupt memory becuse you don't own 4 bytes. Further, you will corrupt the the chars with your int value.

Now you crash.

Please do not code this way.