Multiple calls on same std::string object

[Suman]

Hello All,

Is the following fragment well defined?

std::string some_str("Hello World");
....
some_str.replace(some_str.find("Wor"), strlen("Wor"), other_str);

Or does the nested call on the same string object invoke UB?

Regards,
Suman

[Alf P. Steinbach]

* Suman:

Hello All,

Is the following fragment well defined?

std::string some_str("Hello World");
...
some_str.replace(some_str.find("Wor"), strlen("Wor"), other_str);

Or does the nested call on the same string object invoke UB?

Arguments are evaluated before a function is called.

So, no UB on that account.

--
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[Boris]

On Tue, 10 Apr 2007 14:54:32 +0300, Suman <sk*****@gmail.comwrote:

Hello All,

Is the following fragment well defined?

std::string some_str("Hello World");
...
some_str.replace(some_str.find("Wor"), strlen("Wor"), other_str);

Or does the nested call on the same string object invoke UB?

Why should it? The nested call returns before replace() is called?

Boris

[Suman]

On Apr 10, 5:08 pm, Boris <[e-mail]:

On Tue, 10 Apr 2007 14:54:32 +0300, Suman <[e-mail]:

....

...
some_str.replace(some_str.find("Wor"), strlen("Wor"), other_str);

Or does the nested call on the same string object invoke UB?

Why should it? The nested call returns before replace() is called?

I forgot about the 'argument evaluation before call' part.
Thank you all for your express responses.

Regards,
Suman