enum Question

[amitbern]

Hi, a little Q:
typedef enum
{
NUM0 = 0,
NUM1 = 1,
NUM2 = 2,
NUM3 = 3,
} NUMBER;

NUMBER test=NUM0;

when i'm writing:
test++
i get an error, how can i do the ++ without the need to do casting like:
test=(NUMBER)(test+1);
thanks

[horace1]

Hi, a little Q:
typedef enum
{
NUM0 = 0,
NUM1 = 1,
NUM2 = 2,
NUM3 = 3,
} NUMBER;

NUMBER test=NUM0;

when i'm writing:
test++
i get an error, how can i do the ++ without the need to do casting like:
test=(NUMBER)(test+1);
thanks

in C++ you could overload the operator++() function

[Ganon11]

I'm not sure there's a way to overload operators on enumeratued types...

As far as I know, there is no way to get an enum type from an enum type after incrementing - you have to explicitly cast it.

As an aside, I'm not sure you have to put the = 0, = 1, etc. in the enum values...they are defaulted to the values 0, 1, 2,..., n-1, where n is the number of values.