a question about c++ datatime

[could.net]

I met across a datetime problem when I tried to translate some delphi
code to cpp.
There's a struct called TTimeStamp in delphi,
and this is the cpp equivalent:

struct TTimeStamp
{
int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one
};

My question is, I can only get the current date and time in cpp,
how can I figure out the corresponding TTimeStamp of the current time?

Thanks!

[Jacek Dziedzic]

co*******@gmail.com wrote:

I met across a datetime problem when I tried to translate some delphi
code to cpp.
There's a struct called TTimeStamp in delphi,
and this is the cpp equivalent:

struct TTimeStamp
{
int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one
};

My question is, I can only get the current date and time in cpp,
how can I figure out the corresponding TTimeStamp of the current time?

Well, you can always do a little maths. Each year is 365 days,
each day is 86400000 ms.

Things to remember:
- leap years have a day extra (every 4 years, except when the year
is divisible by 100 and not by 400),
- change of calendar from Julian to Gregorian, if you need dates
from long ago,
- lack of year 0, if you need BCE dates,
- if you are really pedantic about this, additions of 61-st
second on New Years Day Eve, from time to time.

HTH,
- J.

[rossum]

On 17 Dec 2006 03:34:01 -0800, co*******@gmail.com wrote:

>I met across a datetime problem when I tried to translate some delphi
code to cpp.
There's a struct called TTimeStamp in delphi,
and this is the cpp equivalent:

struct TTimeStamp
{
int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one
};

My question is, I can only get the current date and time in cpp,
how can I figure out the corresponding TTimeStamp of the current time?

Thanks!

Run a quick Delphi program to determine what the TTimeStamp is for
some fixed date like 1/1/2000. Use that value as a constant to which
you add the number of days between then and the date you want.

Milliseconds after midnight should be pretty easy.

rossum

[David Harmon]

On 17 Dec 2006 03:34:01 -0800 in comp.lang.c++, co*******@gmail.com
wrote,

> int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one

Note that neither of those have enough range to be very useful.
Should probably be instead.
long Time;
long Date;
and maybe unsigned.

[Greg]

David Harmon wrote:

On 17 Dec 2006 03:34:01 -0800 in comp.lang.c++, co*******@gmail.com
wrote,

int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one

Note that neither of those have enough range to be very useful.
Should probably be instead.
long Time;
long Date;
and maybe unsigned.

A "long" and an "int" are the likely the same (32-bit) size on the
target architecture. And with a 32-bit signed int, TTimeStamp has an
range in excess of 5,600,000 years and a precision of 0.001 seconds.

Greg

[David Harmon]

On 17 Dec 2006 05:30:37 -0800 in comp.lang.c++, "Greg"
<gr****@pacbell.netwrote,

>A "long" and an "int" are the likely the same (32-bit) size on the
target architecture.

No guarantee of that. An int is 16 bits or possibly more;
if you actually need more then say so with long.

[Michal Nazarewicz]

co*******@gmail.com writes:

I met across a datetime problem when I tried to translate some delphi
code to cpp.
There's a struct called TTimeStamp in delphi,
and this is the cpp equivalent:

struct TTimeStamp
{
int Time; // the number of milliseconds that have elapsed since
midnight
int Date; // the number of days since 1/1/0001 plus one
};

My question is, I can only get the current date and time in cpp,
how can I figure out the corresponding TTimeStamp of the current time?

Depending on what you really need you can try something like:

#v+
#include <ctime>

int main() {
long time = std::time(0);
long data = SOME_MAGIC_NUMBER + t / (3600 * 24);
time %= 2600 * 24;
time *= 1000;
return 0;
}
#v+

Where SOME_MAGIC_NUMBER is number of days between 01/01/0001 and start
of the epoch used in time() function. If you need more accuracy you
can try using some platform-specific functions like gettimeofday() on
POSIX.

--
Best regards, _ _
.o. | Liege of Serenly Enlightened Majesty of o' \,=./ `o
..o | Computer Science, Michal "mina86" Nazarewicz (o o)
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