How to represent interger powers in C++?

[heng]

such as 3^4 ?

[Joseph Paterson]

I believe there to be no such representation.
Try:

#include <cmath>
float result = pow(3.0, 4.0)

Joseph.

[Daniel T.]

"heng" <li*********@gmail.comwrote:

such as 3^4 ?

/* pow example */
#include <cstdio>
#include <cmath>

using namespace std;

int main ()
{
cout << "7 ^ 3 = " << pow( 7, 3 ) << '\n';
cout << "4.73 ^ 12 = " << pow( 4.73, 12 ) << '\n';
cout << "32.01 ^ 1.54 = " << pow( 32.01, 1.54 ) << '\n';
}

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[Steven T. Hatton]

heng wrote:

such as 3^4 ?

Option 1) write your own function. (but overloading won't work for
builtins.)
Option 2) Post to comp.std.c++ and suggest it be added.
Option 3) Use the morally unsound conversion to and from floating point
functionality provided with the Standard Library.

There are two other options, but they amount to impractical academic
exercises. These are to use Cpp meta-programming or template
meta-programming.
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