Need Help Fast w/ Counting Consecutives

[c_323_h]

Hi, I need this fast 10pm today. I need help with some code. I am working on this program...a user inputs an integer (For example, 50) between 1 and 100. I have a for loop that generates random numbers between 1 and 100 and iterates according to user input. Now i need to figure out the number of consecutive times that a random numbers occurs below or above the user input.
For example...
cout<<"What's your number?";
cin>>50
cout<<"How many random numbers would you like?";
cin>>10

Output: 24 34 54 67 98 12 34 44 99 10 (random numbers)

This is what I need to figure out...how many times the random numbers occurs consecutively...
24 and 34 are 2 consecutives below 50
54, 67, and 98 a 3 consecutives above 50
12, 34, 44 are 3 consecutives below 50

Thank you!

[D_C]

Here's what I did with STL. Hopefully that's off limits, so you will have to change it around a little. The basic logic should still be the same. That's what you get since memory management owns me. I'm sure there is an easier way, especially by reusing the code at the end, but that's what you can have.

#include <iostream.h>
#include <stdlib.h>
#include <vector>
 
int main()
{
  const unsigned int MAX = 100;
 
  unsigned int number = 0;
  unsigned int limit = 0;
 
  bool prev;
  bool next;
  vector<unsigned int> v;
 
  do
  {
    cout << "What's your number (1-" << MAX-1 << ")?" << endl;
    cin >> number;
  } while(!((0 < number) && (number < MAX)));
 
  do
  {
    cout << "How many numbers (at least one required)?" << endl;
    cin >> limit;
  } while(limit == 0);
  cout << endl;
 
  v = vector<unsigned int>();
  v.reserve(limit);
 
  int i = 0;
  unsigned int temp;
  while(i < limit)
  {
    do
    {
      temp = rand()%MAX;
    }
    while(temp == number);
    v.push_back(temp);
    i++;
  }
 
  vector<unsigned int>::iterator it;
  for(it = v.begin(); it != v.end(); it++)
    cout << *it << " ";
  cout << endl << endl;
 
 
  // variables temp, i and it are reused. It's
  // a bad practice, that's why I'm warning.
  i = 0;
  it = v.begin();
  temp = *it; // not really necessary
  prev = (temp > number);
 
  cout << temp;
  it++;
  i++;
 
  do
  {
    temp = *it; // not really necessary
 
    next = (temp > number);
    if(prev == next)
    {
      if(i++ == 0)
        cout << temp;
      else
        cout << ", " << temp;
    }
    else
    {
      if(i < 2)
        cout << " is ";
      else
        cout << " are ";
 
      if(prev)
        cout << "above ";
      else
        cout << "below ";
 
      cout << number << endl;
 
      i = 1;
      prev = next;
      cout << temp;
    }
    it++;
  } while(it != v.end());
 
    if(i < 2)
      cout << " is ";
    else
      cout << " are ";
 
    if(prev)
      cout << "above ";
    else
      cout << "below ";
 
    cout << number << endl << endl;
 
  system("PAUSE");
  return EXIT_SUCCESS;
}
 

What's your number (1-99)?
0
What's your number (1-99)?
100
What's your number (1-99)?
50
How many numbers (at least one required)?
0
How many numbers (at least one required)?
8

41 67 34 0 69 24 78 58

41 is below 50
67 is above 50
34, 0 are below 50
69 is above 50
24 is below 50
78, 58 are above 50

Press any key to continue . . .