overloading operator ->*

[n2xssvv g02gfr12930]

Does anyone know of an example of overloading operator ->*

Cheers

JB

[Gianni Mariani]

n2xssvv g02gfr12930 wrote:

Does anyone know of an example of overloading operator ->*

Austria C++ has "smart pointers" that do this.

The operator needs to return a pointer.

struct T
{
int x;
};

struct X
{

T * m_ptr;

T * operator->()
{
return m_ptr;
}
};

[n2xssvv g02gfr12930]

Gianni Mariani wrote:

n2xssvv g02gfr12930 wrote:

Does anyone know of an example of overloading operator ->*

Austria C++ has "smart pointers" that do this.

The operator needs to return a pointer.

struct T
{
int x;
};

struct X
{

T * m_ptr;

T * operator->()
{
return m_ptr;
}
};

That's not an example of overloading 'operator ->*' but 'operator ->'.

JB

[ben]

n2xssvv g02gfr12930 wrote:

Does anyone know of an example of overloading operator ->*

Cheers

JB

How do you overload two operators at the same time???
Ben

[John Harrison]

ben wrote:

n2xssvv g02gfr12930 wrote:

Does anyone know of an example of overloading operator ->*

Cheers

JB

How do you overload two operators at the same time???
Ben

->* is only one operator, just like .*

The are used with 'pointers to members'. Look them up in your favourite
C++ book.

john

[Protoman]

What does ->* do? and what does .* do?

[Gianni Mariani]

n2xssvv g02gfr12930 wrote:

That's not an example of overloading 'operator ->*' but 'operator ->'.

Yep, you're right. My mistake.
struct S
{
int z;

int & operator ->* ( int S::* const & x )
{
return this->*x;
}

};

struct Y
{
int z;

template <typename T>
T & operator ->* ( T Y::* const & x )
{
return this->*x;
}

};

int main()
{
S s;
int S::* pmz = &S::z;

s->*( pmz ) = 3;

Y y;
int Y::* pmy = &Y::z;

y->*( pmy ) = 3;
}