struct ?

[tvn007]

I am working on the data struc. below:
is there way I can abbrev. the expression below to avoid long
expression.
Thanks......
///////////////////////////////////////////////////////////////////////////////////
#include <iostream>
#include <string>
#include <fstream>
#include <sstream>
using namespace std;
const int MAX=50;
struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;

int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);

/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;
//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
ptrstudent++;
}
}

[Ron Natalie]

tvn007 wrote:

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
istream& operator>> (istream& is) (
is >> bypassed;
is >> name
is >> midterm;
is >> quiz
is >> final;
is >> testname;
return is;
}
}student[MAX],*ptrstudent;

int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);

/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;
anyname >> *ptrstudent;
//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
ptrstudent++;
}
}

[Richard Herring]

In message <43***********************@news.newshosting.com> , Ron Natalie
<ro*@spamcop.net> writes

tvn007 wrote:

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
istream& operator>> (istream& is) (

If its _left_ operand is to be an istream, this can't be a member
function of Record_info. It has to be a non-member function with two
arguments.

friend istream & operator>>(istream & is, Record_info & rec) {
is >> bypassed; is >> rec.bypassed; // etc. is >> name
is >> midterm;
is >> quiz
is >> final;
is >> testname;
return is;
}

}student[MAX],*ptrstudent;

int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);
/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

anyname >> *ptrstudent;

///////////////////////////////////////////////////////////////////////
///////////////////////////////////////////////////////
ptrstudent++;
}
}

--
Richard Herring

[tvn007]

I am not sure if it will work since I am using struct array and
pointer.

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;
ptrstudent = student;

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;
anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

[Jakob Bieling]

tvn007 <tv****@hotmail.com> wrote:

I am not sure if it will work [..]

Have you tried it?
--
jb

(reply address in rot13, unscramble first)

[Richard Herring]

In message <11**********************@g43g2000cwa.googlegroups .com>,
tvn007 <tv****@hotmail.com> writes

I am not sure if it will work
Not sure if _what_ will work? Please quote some context.
since I am using struct array and
pointer.
I don't think that's relevant. Fundamentally you want to implement
operator>>(istream&, Record_info &). If the Record_info happens to be an
array element or the target of a pointer it makes no difference.
struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;
ptrstudent = student;

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;
anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

anyname >> *ptrstudent;

--
Richard Herring