How come this is illegal?
const int N = 10;
double a[ N ];
I get "error: variable-size type declared outside of any function".
What's the reason behind this syntax rule? 11 5179 ge*****@gmail.com writes: How come this is illegal?
const int N = 10; double a[ N ];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
N is a variable whose value is set at run-time.
Hence the size of 'a' cannot be known at compile time.
--
Chris.
gene...@gmail.com wrote: How come this is illegal?
const int N = 10; double a[ N ];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
In C, const does not mean constant, it means read only.
C99 supports variable length arrays, but only with automatic
(local to function) storage.
--
Peter
<ge*****@gmail.com> wrote in message
news:11**********************@f14g2000cwb.googlegr oups.com... How come this is illegal?
const int N = 10; double a[ N ];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
A const declaration creates a read-only variable. If you want a true
constant who's value is known at compile time, then do this:
#define N 10
--
Daniel Rudy ge*****@gmail.com wrote: How come this is illegal?
const int N = 10; double a[ N ];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
There is no syntax problem here; no "syntax rule" is violated.
This is a semantic violation, namely, the syntactically correct but
non-constant `N' is used in a context where a constant expression
is required. (As others have explained, `const' is only 62.5%
`constant'.)
--
Eric Sosman es*****@acm-dot-org.invalid
Daniel Rudy wrote: A const declaration creates a read-only variable. If you want a true
constant who's value is known at compile time, then do this:
#define N 10
Wasn't the point of having "const" (in part) to be able to replace
#define? ge*****@gmail.com wrote: How come this is illegal?
const int N = 10; double a[N];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
This is a flaw in the design of the C computer programming language
which was fixed in the C++ computer programming language
but could not be fixed in C
because so much legacy code depended upon it. ge*****@gmail.com wrote: Daniel Rudy wrote:
A const declaration creates a read-only variable. If you want a true
constant who's value is known at compile time, then do this:
#define N 10
Wasn't the point of having "const" (in part) to be able to replace #define?
Yes. In *C++*. Not C.
HTH,
--ag
--
Artie Gold -- Austin, Texas http://it-matters.blogspot.com (new post 12/5) http://www.cafepress.com/goldsays ge*****@gmail.com wrote: Daniel Rudy wrote:
A const declaration creates a read-only variable. If you want a true constant who's value is known at compile time, then do this:
#define N 10
Wasn't the point of having "const" (in part) to be able to replace #define?
Not in the C language. If you want C++ that is another newsgroup.
--
Chuck F (cb********@yahoo.com) (cb********@worldnet.att.net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home.att.net> USE worldnet address!
E. Robert Tisdale wrote: ge*****@gmail.com wrote: How come this is illegal?
const int N = 10; double a[N];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
This is a flaw in the design of the C computer programming language which was fixed in the C++ computer programming language but could not be fixed in C because so much legacy code depended upon it.
C took the const keyword from C++. Thus, C++ did not 'fix'
existing C usage of const, and there was no 'legacy code'
to speak of.
--
Peter
At about the time of 5/10/2005 6:50 PM, ge*****@gmail.com stated the
following: Daniel Rudy wrote:
A const declaration creates a read-only variable. If you want a true
constant who's value is known at compile time, then do this:
#define N 10
Wasn't the point of having "const" (in part) to be able to replace #define?
AFAIK, that applies only in C++. In C, you still have to use #define
for true compile time constants.
--
Daniel Rudy
Email address has been encoded to reduce spam.
Remove all numbers, then remove invalid, email, no, and spam to reply.
On Tue, 10 May 2005 19:17:30 -0700, E. Robert Tisdale wrote: ge*****@gmail.com wrote:
How come this is illegal?
const int N = 10; double a[N];
I get "error: variable-size type declared outside of any function". What's the reason behind this syntax rule?
This is a flaw in the design of the C computer programming language which was fixed in the C++ computer programming language but could not be fixed in C because so much legacy code depended upon it.
How would "fixing" this in C break legacy code?
Lawrence This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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