Expression B b(A()) seemed no effect?

[wij]

Hi:
I encountered an expression B b(A()) which seemd to have no runtime
code compiled (as in the following example). Can anybody explain
this to me? Thank you.

// Build: g++ t.cpp (GCC version 3.4.2)
//
// [mypc]$./a.out
// strange?
// [mypc]$
//
#include <iostream>

class A {
public:
A() { std::cerr << "A ";
throw (const char*)"A_throw"; };
};

class B {
public:
B(const A&) { std::cerr << "B(A) "; };
};

int main(void)
{
try {
B b(A()); // constructing b object, no effect?
// expecting: "A_throw"
throw (const char*)"strange?";
}
catch(const char* str) {
std::cerr << str << '\n';
}
catch(...) {
std::cerr << "unknown\n";
};

return(0);
};

[Markus Moll]

Hi

wi*@seed.net.tw wrote:

Hi:
I encountered an expression B b(A()) which seemd to have no runtime
code compiled (as in the following example). Can anybody explain
this to me? Thank you.

B b(A());
is the declaration of a function b returning an object of type B and taking
a function as parameter.

A some_func();
B b(A());
B my_b = b(some_func);
Markus

[John Carson]

<wi*@seed.net.tw> wrote in message
news:11*********************@z14g2000cwz.googlegro ups.com

Hi:
I encountered an expression B b(A()) which seemd to have no runtime
code compiled (as in the following example). Can anybody explain
this to me? Thank you.

// Build: g++ t.cpp (GCC version 3.4.2)
//
// [mypc]$./a.out
// strange?
// [mypc]$
//
#include <iostream>

class A {
public:
A() { std::cerr << "A ";
throw (const char*)"A_throw"; };
};

class B {
public:
B(const A&) { std::cerr << "B(A) "; };
};

int main(void)
{
try {
B b(A()); // constructing b object, no effect?
// expecting: "A_throw"
throw (const char*)"strange?";
}
catch(const char* str) {
std::cerr << str << '\n';
}
catch(...) {
std::cerr << "unknown\n";
};

return(0);
};

Further to Markus's point, you can achieve your intended effect with:

B b = A();

--
John Carson

[Victor Bazarov]

John Carson wrote:

[..]
Further to Markus's point, you can achieve your intended effect with:

B b = A();

Or

B b((A()));

V

[wij]

Victor Bazarov wrote:

John Carson wrote:

[..]
Further to Markus's point, you can achieve your intended effect with:
B b = A();

Or
B b((A()));

Thanks for the fixup, But what is the reason?
So I can use it in genreal cases.

[benben]

If a statement can be either parsed as function declaration or object
instantiation, the compiler will prefer the former.

ben

[Jonathan Mcdougall]

wi*@seed.net.tw wrote:

Victor Bazarov wrote:

John Carson wrote:

[..]
Further to Markus's point, you can achieve your intended effect with:
B b = A();

Or
B b((A()));

Thanks for the fixup, But what is the reason?
So I can use it in genreal cases.

http://www.gotw.ca/gotw/075.htm
Jonathan

[wij]

Jonathan Mcdougall wrote:

...
http://www.gotw.ca/gotw/075.ht m

Thanks for the link, it explains well.