"can't convert parameter" error

[Ian Lazarus]

// why is the error message being generated?
// Microsoft Visual C/C++ 5.0

class Bar
{
public:
void Log(const char* p){ }
};

class Foo : public Bar
{
public:
void Log(int x){ }
};

int main()
{
Foo foo;
foo.Log("foo bar"); // error message below

return(0);
}

// error C2664: 'Log' : cannot convert parameter 1 from 'char [8]' to 'int'

[White Wolf]

Ian Lazarus wrote:

// why is the error message being generated?
// Microsoft Visual C/C++ 5.0

class Bar
{
public:
void Log(const char* p){ }
};

class Foo : public Bar
{
public:
using Bar::Log;
void Log(int x){ }
};

int main()
{
Foo foo;
foo.Log("foo bar"); // error message below

return(0);
}

// error C2664: 'Log' : cannot convert parameter 1 from 'char [8]' to
'int'

Bar::Log hides Foo:Log as a name.

--
WW aka Attila
:::
'Meesa Jar Jar Binks of Borg! Yousa gonna be Assim'lated!'

[White Wolf]

White Wolf wrote:

Bar::Log hides Foo:Log as a name.

Ehem, the other way around

--
WW aka Attila
:::
When all you have is a hammer, the whole world looks like a nail.

[Oliver Fleischmann]

On Sat, 31 Jan 2004 21:54:56 GMT, "Ian Lazarus" <no****@nowhere.net>
wrote:

// why is the error message being generated?
// Microsoft Visual C/C++ 5.0

class Bar
{
public:
void Log(const char* p){ }
};

class Foo : public Bar
{
public:
void Log(int x){ }
};

int main()
{
Foo foo;
foo.Log("foo bar"); // error message below

return(0);
}

// error C2664: 'Log' : cannot convert parameter 1 from 'char [8]' to 'int'

Hi,

this error is created, because the "Log" method of your class "Foo"
takes an integer as parameter.
"Foo" inherets the Log function from Bar but you overwrite it in Foo
so it's parameter isn't a "const char *" anymore but your "int x".

Olli