suggest parentheses around assignment used as truth value

[jamestp]

the errors come up as suggest parentheses around assignment used as truth value which it says for the lines 7,10,13,16,19 and im just wondering what it is that is wrong with it if anyone could let me know cause im new to this. heres my code:

#include <stdio.h>
 
    int main(int argc,char*argv[]){
    int integer;
    printf("please enter an integer \n");
    scanf("%d", &integer);
    if (integer=(1)){
    printf ("you entered: \n one");
}
    if (integer=(2)){;
    printf ("you entered: \n two");
}
    if (integer=(3)){;
    printf ("you entered: \n three");
}
    if (integer=(4)){;
    printf ("you entered: \n four");
}
    if (integer=(5)){;
    printf ("you entered: \n five");
}
    if (integer<1){;
    printf ("you entered a number less then one\n");
}
    if (integer>5){;
    printf ("you entered a number greater than five");
}
    return 0;
}
 
 

the lines 7, 10, 13, 16 19 are the ones with the "integer=number " part

[weaknessforcats]

This code:

 if (integer=(1)){
etc...

should be:

 if (integer == 1){
etc...

The = may mean "equals" in mathematics but in C and C++ it means "assignment ". The original code would try to change the integer entered to 1 instead of testng it for 1.

Note that if (integer=(1)) will always be true since 1 is true. That means the code following it can never be reached and that is what the compiler is frowning about.