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How to assign a 2d array to a memory address.

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HI - I have a 2d array of uint32's :

Expand|Select|Wrap|Line Numbers
  1. uint32 x[4][5];
and I want that array to be assigned to a certain address (which is a set of registers) :

Expand|Select|Wrap|Line Numbers
  1. uint32 *addr = 0x12345678;
  2.  
HOW do I assign the 2d array to the address? I know it's not right but I want to do this:

&x = addr;

helppp
May 21 '10 #1
1 4220
Banfa
9,065 Recognized Expert Moderator Expert
You can't assign an address to an array, you can onlyassign an address to a pointer.

Now assuming your address points to a block of memory with the array you've given what you need is a pointer to an array of that type. To declare a pointer to an array you sound the name and * with ()

int *a[5]; // An array of 5 pointers to ints

int (*a)[5]; // A pointer to an array of ints

So you would do

uint32 (*addr)[4][5] = 0x12345678;

If this is C++ you will need a cast. Then you can access this as

(*addr)[2][1]
May 21 '10 #2

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