question about local class in a function

[Nan Li]

Hello,
Can any one explain why the following code cannot get compiled ??
Thanks.

#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
struct A
{
void operator()(int i)
{
cout << i << endl;
}
};

vector<intv(3);

for_each( v.begin(), v.end(), A() );

return 0;
}

c.cpp: In function 'int main(int, char**)':
c.cpp:21: error: no matching function for call to
'for_each(__gnu _cxx::__normal_ iterator<int*, std::vector<int ,
std::allocator< int >, __gnu_cxx::__no rmal_iterator<i nt*,
std::vector<int , std::allocator< int >, main(int, char**)::A)'

[Ian Collins]

Nan Li wrote:

Hello,
Can any one explain why the following code cannot get compiled ??
Thanks.

#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
struct A
{
void operator()(int i)
{
cout << i << endl;
}
};

vector<intv(3);

for_each( v.begin(), v.end(), A() );

return 0;
}

c.cpp: In function 'int main(int, char**)':
c.cpp:21: error: no matching function for call to
'for_each(__gnu _cxx::__normal_ iterator<int*, std::vector<int ,
std::allocator< int >, __gnu_cxx::__no rmal_iterator<i nt*,
std::vector<int , std::allocator< int >, main(int, char**)::A)'

gcc trying to tell you in its own obscure way that you can't use a local
type as a template argument.

--
Ian Collins.

[Salt_Peter]

On Feb 17, 2:55 am, Nan Li <nan.l...@gmail .comwrote:

Hello,
Can any one explain why the following code cannot get compiled ??
Thanks.

#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
struct A
{
void operator()(int i)
{
cout << i << endl;
}
};

vector<intv(3);

for_each( v.begin(), v.end(), A() );

return 0;

}

c.cpp: In function 'int main(int, char**)':
c.cpp:21: error: no matching function for call to
'for_each(__gnu _cxx::__normal_ iterator<int*, std::vector<int ,
std::allocator< int >, __gnu_cxx::__no rmal_iterator<i nt*,
std::vector<int , std::allocator< int >, main(int, char**)::A)'

Your operator expects a parameter.
Since you'ld end up using a placeholder...
Why not just use boost::lambda

#include <iostream>
#include <vector>
#include <algorithm>
#include "boost/lambda/lambda.hpp"

int main()
{
using boost::lambda:: _1;
std::vector< int v(3, 9);
std::for_each( v.begin(), v.end(), std::cout << _1 << '\n' );
}

/*
9
9
9
*/

http://www.boost.org/doc/html/lambda.html

[Jerry Coffin]

In article <33e8504b-bca1-411f-bf19-b619a4846c67
@q70g2000hsb.go oglegroups.com> , na******@gmail. com says...

Hello,
Can any one explain why the following code cannot get compiled ??
Thanks.

#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>

using namespace std;

int main(int argc, char* argv[])
{
struct A
{
void operator()(int i)
{
cout << i << endl;
}
};

vector<intv(3);

for_each( v.begin(), v.end(), A() );

return 0;
}

Local types don't have linkage, so they can't be used as template
parameters.

Fortunately, the entire type and for_each that uses it work out to:

std::copy(v.beg in(), v.end(),
std::ostream_it erator<int>(std ::cout, "\n"));

--
Later,
Jerry.

The universe is a figment of its own imagination.