I've done some searching in this newsgroup and on the internet and
haven't found an answer, so I thought I'd ask here... :-)
I don't understand why full specialization of a member function
template in a class template is only valid if you fully specialize the
class template as well. Consider the following example:
[header]
template<class T, int ID>
class RSMixin : public T
{
...
template <typename T2>
void setAttribute (std::string name, T2 value);
}
[implementation]
template<class T, int ID>
template<>
void
RSMixin<T, ID>::setAttribu te (std::string name, bool value)
{ }
I understand that this isn't valid, but I don't really understand the
rationale behind why.
RSMixin<Generic Driver, 0foo;
foo.setAttribut e ("some attribute", true);
should generate:
void RSMixin<Generic Driver, 0>::setAttribut e(std::string, bool);
This seems unambiguous to me, but maybe someone can point out a more
difficult situation where the compiler wouldn't be able to figure it
out?
--
Nick 1 1439
On Sat, 10 Nov 2007 20:15:42 -0000, Nick Bastin
<ni*********@gm ail.comwrote in comp.lang.c++:
I've done some searching in this newsgroup and on the internet and
haven't found an answer, so I thought I'd ask here... :-)
I don't understand why full specialization of a member function
template in a class template is only valid if you fully specialize the
class template as well. Consider the following example:
[header]
template<class T, int ID>
class RSMixin : public T
{
...
template <typename T2>
void setAttribute (std::string name, T2 value);
}
[implementation]
template<class T, int ID>
template<>
void
RSMixin<T, ID>::setAttribu te (std::string name, bool value)
{ }
I understand that this isn't valid, but I don't really understand the
rationale behind why.
RSMixin<Generic Driver, 0foo;
foo.setAttribut e ("some attribute", true);
should generate:
void RSMixin<Generic Driver, 0>::setAttribut e(std::string, bool);
This seems unambiguous to me, but maybe someone can point out a more
difficult situation where the compiler wouldn't be able to figure it
out?
I would suggest you post this to comp.std.c++, which is a moderated
group. Its purpose is discussion of the (past, present, and future)
C++ language standard and such issues as the rationale for various
decisions made in creating the standard.
This group, and comp.lang.c++.m oderated, primarily discuss the usage
of the language as it exists, not why the standard is as it is.
--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
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last post by:
Hi
Template partial specialization always seems like a fairly
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I am trying to implement the input sequence type (from Stroustrup
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Hi,
If you've got a template class with lots of methods,
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What you need to do there is specialize the template for your
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If there's only 1 template parameter, one can specialize the method
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-X
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Hello all,
I am trying to create a full specialization of a member function template of
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Line 29: 'foo<T1>::bar' : illegal use of explicit template arguments
Line 29: 'bar' : unable to match function definition to an existing
declaration
What am I doing wrong?
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last post by:
I've never understood the rationale of allowing partial, but not
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struct A {
template <typename T1, typename T2>
struct B {};
// this is not allowed:
template <>
struct B<int, float> {};
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