Suppose I have
vector<intv;
vector<int>::co nst_iterator citer = v.begin( );
Here which version of begin( ) is called ? const or non-const
version ?
Kindly explain
Thanks
V.Subramanian 3 2427 su************* *@yahoo.com, India wrote:
Suppose I have
vector<intv;
vector<int>::co nst_iterator citer = v.begin( );
Here which version of begin( ) is called ? const or non-const
version ?
Should be non-const ...
Kindly explain
.... because v is not const.
Best
Kai-Uwe Bux
On 2007-10-25 09:59, su************* *@yahoo.com, India wrote:
Suppose I have
vector<intv;
vector<int>::co nst_iterator citer = v.begin( );
Here which version of begin( ) is called ? const or non-const
version ?
The non-const version. The reason for this is the fact that v is not
const. Consider the following example:
#include <vector>
void foo(const std::vector<int >& v)
{
std::vector<int >::const_iterat or it = v.begin();
}
int main()
{
std::vector<int v;
std::vector<int >::iterator it = v.begin();
std::vector<int >::const_iterat or cit = v.begin();
foo(v);
}
In foo() you must use a const_iterator since v is const, in main()
however you can use either since a const_iterator can be constructed
from an iterator. Notice though that I have not found anything in the
standard requiring this, so it might not be portable.
--
Erik Wikström
On 2007-10-25 03:59:36 -0400, "su************ **@yahoo.com, India"
<su************ **@yahoo.comsai d:
Suppose I have
vector<intv;
vector<int>::co nst_iterator citer = v.begin( );
Here which version of begin( ) is called ? const or non-const
version ?
As everyone else has said, non-const. If that's a problem, there are
two ways to call the const version.
((const vector<int>&)v) .begin();
v.cbegin();
The latter is a recent addition to the C++0x specification, so chances
are your library doesn't have it.
--
Pete
Roundhouse Consulting, Ltd. ( www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
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