Does standard say anything about this situation? or it is an undefined
behavior?
Thanks
------------------------------
map<int, inttest;
test[1] = 1;
test[2] = 2;
test[3] = 3;
test.erase(test .find(1), test.find(2)); // basically this is an
invalid range to erase.
map<int, int>::iterator pos = test.begin();
test.erase(pos, --pos); // another example of invalid range.
---------------------------- 2 1589
newbie <mi******@yahoo .comwrote in news:1185514036 .005960.85290
@g12g2000prg.go oglegroups.com:
Does standard say anything about this situation? or it is an undefined
behavior?
Thanks
------------------------------
map<int, inttest;
test[1] = 1;
test[2] = 2;
test[3] = 3;
test.erase(test .find(1), test.find(2)); // basically this is an
invalid range to erase.
That's invalid? Perhaps you meant find(2) then find(1) ?
map<int, int>::iterator pos = test.begin();
test.erase(pos, --pos); // another example of invalid range.
----------------------------
Yep, they're both Undefined Behaviour. It's the programmer's
responsibility to ensure that the ranges passed to erase() (as in: the
first iterator is "less than" or equal to the second iterator.
On Jul 27, 6:38 am, Andre Kostur <nntps...@kostu r.netwrote:
newbie <mitbb...@yahoo .comwrote in news:1185514036 .005960.85290
@g12g2000prg.go oglegroups.com:
Does standard say anything about this situation? or it is an undefined
behavior?
Thanks
------------------------------
map<int, inttest;
test[1] = 1;
test[2] = 2;
test[3] = 3;
test.erase(test .find(1), test.find(2)); // basically this is an
invalid range to erase.
That's invalid? Perhaps you meant find(2) then find(1) ?
Right, I meant the other way. test.erase(test .find(2), test.find(1));
>
map<int, int>::iterator pos = test.begin();
test.erase(pos, --pos); // another example of invalid range.
----------------------------
Yep, they're both Undefined Behaviour. It's the programmer's
responsibility to ensure that the ranges passed to erase() (as in: the
first iterator is "less than" or equal to the second iterator.
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