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[Warning] passing `const double' for converting

71 New Member
I get this long and hard to understand warning when I call a constructor:

AssocArray<doub le, string> myAssocArray(na mes, myArr);

the code for the constructor:

template <class V, class AI, class I, class S>
AssocArray<V, AI, I, S>::AssocArray( const list<AI>& names, const Array<V, I, S>& source)
{

I curr = source.MinIndex ();

typename list<AI>::const _iterator it;
for (it = names.begin(); it != names.end(); it++)
{
internal_array. insert(pair<AI, I>(*it, source[curr]));

curr++;
}


}

The warning that I get:

[Warning] passing `const double' for converting 2 of `std::pair<_T1, _T2>::pair(cons t _T1&, const _T2&) [with _T1 = std::string, _T2 = int]'

I would appreciate any insights.
Jul 5 '07 #1
2 2752
weaknessforcats
9,208 Recognized Expert Moderator Expert
You need a pair with a const double:

Expand|Select|Wrap|Line Numbers
  1. pair<int, const double> obj;
  2.  
None of your pair types are const.

Maybe:
Expand|Select|Wrap|Line Numbers
  1. internal_array.insert(pair<AI,const I>(*it, source[curr]));
  2.  
Assuming l is a double.
Jul 6 '07 #2
curious2007
71 New Member
OK, thanks. Somehow once I restarted the compiler I stopped getting the errors.
Jul 6 '07 #3

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