how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
and how?
Jun 21 '07
43  2383 
On Thu, 21 Jun 2007 14:56:39 -0000, in comp.lang.c ,
"bh********@gma il.com" <bh********@gma il.comwrote:
>
what i want actually is how much size will be allocated for above
structuer in a 16 bit machine
There is no correct answer. Depending on compiler settings, hardware
requirements and so on, it could be anything from seven bytes upwards.
Its impossible to say.
Why do you need to know?
--
Mark McIntyre
"Debugging is twice as hard as writing the code in the first place.
Therefore, if you write the code as cleverly as possible, you are,
by definition, not smart enough to debug it."
--Brian Kernighan
"bh********@gma il.com" wrote:
>
how much memory is allocated for following structure
struct bharath {
int b;
char c;
float d;
}
and how?
Exactly "sizeof(str uct bjarath);", in bytes. How is system
dependant.
--
<http://www.cs.auckland .ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfoc us.com/columnists/423>
<http://www.aaxnet.com/editor/edit043.html>
cbfalconer at maineline dot net
--
Posted via a free Usenet account from http://www.teranews.com bh********@gmai l.com wrote:
how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
This is, for some reason, a common newbie question. It doesn't need to
be. When it comes to struct sizes, there are only two things to keep in
mind:
1. The actual size is implementation-specific. That means it varies
from compiler to compiler, perhaps even with the same compiler
depending on options. There's no way to know from code inspection.
2. When you need to know the size in a program, the sizeof operator
will tell you. The actual value is of little importance.
Brian bh********@gmai l.com wrote:
how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
^^ ';' needed
None, until an instance of that structure is declared.
If you have one
struct bharath foo;
the space allocated is
sizeof foo
or
sizeof(struct bharath)
and is at least
sizeof(int)+siz eof(float)+1
and how?
With whatever mechanism your compiler allocates space for other variables.
<bh********@gma il.comha scritto nel messaggio news:11******** **************@ q19g2000prn.goo glegroups.com.. .
how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
None, because you are not declaring an object.
If you wrote
struct bharath {
int b;
char c;
float d;
} a;
It would allocate sizeof a bytes, i.e. sizeof(struct bharath)
bytes.
and how?
The same way it is allocated for any other object.
<bh********@gma il.comha scritto nel messaggio news:11******** *************@q 19g2000prn.goog legroups.com...
On Jun 21, 7:49 pm, Clever Monkey <spamt...@cleve rmonkey.org.INV ALID>
wrote:
>balu wrote:
On Jun 21, 7:33 pm, Richard Heathfield <r...@see.sig.i nvalidwrote:
bharath...@gma il.com said:
>>how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
None. It's a type, not an object.
[Please use a newsreader that understands how to trim sigs, or trim them
yourself. I've done this for you here.]
let the int size is 4B then the allocation will be?
i want to know the info regarding padding or some other else related
to padding?
This is exactly the sort of thing that people talk about when they say
something is implementation specific. That is, once you actually
allocate for a type, the specifics of how that memory is allocated is
not necessarily dictated by the Standard.
Simply defining (or is it declaring?) the type, of course, allocates no
memory.
--
clvrmnky <mailto:spamt.. .@clevermonkey. org>
Direct replies will be blacklisted. Replace "spamtrap" with my name to
contact me directly.
what i want actually is how much size will be allocated for above
structuer in a 16 bit machine
It doesn't even have to be the same on all 16-bit machines, or even
on the same machine with different compilers.
"bh********@gma il.com" <bh********@gma il.comwrites:
how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
and how?
The comp.lang.c FAQ is at <http://www.c-faq.com/>. Section 2 covers
structures (as well as unions and enumerations). Read it. If you're
still confused, come back and ask again.
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister" bh********@gmai l.com wrote:
On Jun 21, 7:49 pm, Clever Monkey <spamt...@cleve rmonkey.org.INV ALID>
wrote:
>balu wrote:
On Jun 21, 7:33 pm, Richard Heathfield <r...@see.sig.i nvalidwrote:
bharath...@gma il.com said:
>>how much memory is allocated for following structure
struct bharath
{
int b;
char c;
float d;
}
(fx:snipping)
what i want actually is how much size will be allocated for above
structuer in a 16 bit machine
It depends on the implementation.
Really.
A "16-bit machine" (and what /that/ means isn't unambiguous) might have
a C implementation which used 32-bit ints. Or 16-bit ints. It might have
32-bit floats. Or 64. Floats might need to be allocated on 16-bit boundaries.
Or 32-bit boundaries. Or 8-bit boundaries. chars might be 8 bits wide.
Or 16. You might be able to /select/ these things with, say, command-line
switches.
It depends on the implementation.
--
Chris "just like life, really" Dollin
Hewlett-Packard Limited registered no:
registered office: Cain Road, Bracknell, Berks RG12 1HN 690597 England
"bh********@gma il.com" <bh********@gma il.comwrote:
# how much memory is allocated for following structure
None. Structures only exist in the compiler; in the code
you have blocks of allocated memory and offsets into them.
A variable of type T needs no more than sizeof(T) char sized
units allocated on appropriate memory boundary.
# struct bharath
# {
# int b;
# char c;
# float d;
# }
A variable of type (struct bharath) will be allocated at
least sizeof(struct bharath) bytes. How a compiler allocates
the space is really up to the compiler. If you need to know
there are field offset macros to find otu where each field
begins in the variable's allocated space.
--
SM Ryan http://www.rawbw.com/~wyrmwif/
I hope it feels so good to be right. There's nothing more
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