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Using std:.pair right

I have made this little test with std::pair:

test<intt1(1);
test<intt2(2);
std::pair<test< int>,test<int mypair = std::make_pair( t1,t2);

where test is a template class I wrote. It seems a bit cumbersome to
make a pair are there any better way to do it than the above procedure?
Jun 15 '07
18 2060
Rolf Magnus wrote:
Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.
Any better suggestion for saving the few keypresses?
Jun 17 '07 #11
On 2007-06-17 13:20, Juha Nieminen wrote:
Rolf Magnus wrote:
>Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.

Any better suggestion for saving the few keypresses?
Baltimore's suggestion about using a typedef.

--
Erik Wikström
Jun 17 '07 #12
Erik Wikström wrote:
On 2007-06-17 13:20, Juha Nieminen wrote:
>Rolf Magnus wrote:
>>Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.

Any better suggestion for saving the few keypresses?

Baltimore's suggestion about using a typedef.
Which - btw- I already made a day before.

Jun 17 '07 #13
Erik Wikström wrote:
> Any better suggestion for saving the few keypresses?

Baltimore's suggestion about using a typedef.
That only saves keypresses if you have to create more than one
pair. With only one it requires more keypresses.
Jun 17 '07 #14
On Jun 17, 2:44 am, Rolf Magnus <ramag...@t-online.dewrote:
Juha Nieminen wrote:
Ian Collins wrote:
desktop wrote:
I have made this little test with std::pair:
> test<intt1(1);
test<intt2(2);
std::pair<test< int>,test<int mypair = std::make_pair( t1,t2);
>where test is a template class I wrote. It seems a bit cumbersome to
make a pair are there any better way to do it than the above procedure?
What would you suggest?
Using 'auto' in the upcoming standard?

Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.
Deducing the type of variable from its initializer expression has
already been voted into C++, so as a feature it has already been
added. Moreover, I see little reason why the poster would have to wait
until the "majority" of C++ compilers supported a

Jun 17 '07 #15
On Jun 17, 2:44 am, Rolf Magnus <ramag...@t-online.dewrote:
Juha Nieminen wrote:
Ian Collins wrote:
desktop wrote:
I have made this little test with std::pair:
> test<intt1(1);
test<intt2(2);
std::pair<test< int>,test<int mypair = std::make_pair( t1,t2);
>where test is a template class I wrote. It seems a bit cumbersome to
make a pair are there any better way to do it than the above procedure?
What would you suggest?
Using 'auto' in the upcoming standard?

Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.
Actually, deducing the type of variable from its initializer
expression has already been voted into C++, so it's only a matter of
lobbying C++ compiler vendors to support it in their compilers.
Furthermore, I see no reason why the original poster would have to
wait until the "majority" of C++ compilers support this feature -
instead of just the C++ compiler he happens to be using.

I would point out that the "auto" keyword saves a few keystrokes only
if you already know what those keystrokes should be. But figuring out
the return type of a function call may not always be easy (e.g.
boost::bind) or even be possible (in a portable way). What type, for
example, does std::tr1::mem_f n() return:

struct A
{
int f();
};

??? mf = std::tr1::mem_f n( &A::f);

Hint: it's unspecified.

Greg
Jun 17 '07 #16
On Jun 17, 11:44 am, Rolf Magnus <ramag...@t-online.dewrote:
Juha Nieminen wrote:
Ian Collins wrote:
desktop wrote:
I have made this little test with std::pair:
> test<intt1(1);
test<intt2(2);
std::pair<test< int>,test<int mypair = std::make_pair( t1,t2);
>where test is a template class I wrote. It seems a bit cumbersome to
make a pair are there any better way to do it than the above procedure?
What would you suggest?
Using 'auto' in the upcoming standard?
Best suggestion ever: Wait a few year until they add that feature to the
language. Then wait another few years until the majority of compilers
actually implement it. Then you can save a few keypresses.
More than keystrokes, I think the point is maintainability .
Modify t1 and t2 to be test<long>, and everything works with
auto.

--
James Kanze (Gabi Software) email: ja*********@gma il.com
Conseils en informatique orientée objet/
Beratung in objektorientier ter Datenverarbeitu ng
9 place Sémard, 78210 St.-Cyr-l'École, France, +33 (0)1 30 23 00 34
Jun 17 '07 #17
In article <46************ **********@news .song.fi>,
no****@thanks.i nvalid says...
Erik Wikström wrote:
Any better suggestion for saving the few keypresses?
Baltimore's suggestion about using a typedef.
That only saves keypresses if you have to create more than one
pair. With only one it requires more keypresses.
I haven't actually counted characters, but I believe this typedef should
save a few keystrokes even the first time around:

typedef test<intti;

ti t1(1), t2(2);

std::pair<ti, timypair=std::m ake_pair(t1, t2);

--
Later,
Jerry.

The universe is a figment of its own imagination.
Jun 17 '07 #18
"desktop" <ff*@sss.comwro te in message
news:f4******** **@news.net.uni-c.dk...
>I have made this little test with std::pair:
test<intt1(1);
test<intt2(2); std::pair<test< int>,test<int mypair =
std::make_pair( t1,t2);
where test is a template class I wrote. It seems a bit cumbersome to make
a pair are there any better way to do it than the above procedure?
How about

std::pair<test< int>,test<int mypair(t1, t2);

? It might even be that you can write

std::pair<test< int>,test<int mypair(1, 2);

depending on your definition of test.
Jun 18 '07 #19

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