help me rectify the code---why cant i initialize the double variable sum1=0

[Shashidhar Patil]

here is the code

#include<iostre am.h>
#include<math.h >
#include<conio. h>
class legendre
{
private:
int c,b,z,zz,xx,yy, fact;
double a,nt,x,y,aa,fin al,bb,cc;
double sum1=0;
public:
int factorial(int n)
{
if (n==0)
return 1;
else
{
fact=n*factoria l(n-1);
return fact;
}
}
// legendre();
void calculate(int l,int m,double theta)
{
a=(2*l+1)/2;
b=1- m%1;
c=1+ m%1;
zz=factorial(l) ;
xx=factorial(c) ;
yy=factorial(z) ;
bb=factorial(b)/zz;
cc=factorial(c)/zz;
nt=sqrt(a*bb*cc );
for(int q=0; q<=b/2; q++)
{
z=2*l-2*q;
x=z/(factorial(l-q)*factorial(q) );
y=yy/(xx*factorial(z-c));
sum1+=((pow(-1,l+q))*x*y*(po w(cos(theta),b-2*q)));
}

aa=nt*(pow(sin( theta),m)/pow(2,l));
final=aa*sum1;
cout<<"the value of the expression : "<<final<<e ndl;
}
};

void main()
{
int l,m;
double theta;
cout<<"enter the values for l, m and theta: "<<endl;
cin>>l>>m>>thet a;
legendre expression;
expression.calc ulate(l,m,theta );
getch();
}

[Howard]

"Shashidhar Patil" <hi******@yahoo .com> wrote in message
news:fb******** *************** *@posting.googl e.com...

here is the code

#include<iostre am.h>
#include<math.h >
#include<conio. h>
class legendre
{
private:
int c,b,z,zz,xx,yy, fact;
double a,nt,x,y,aa,fin al,bb,cc;
double sum1=0;
public:

When you add an initializer statement to a declaration, it becomes a
definition, not a declaration, and definitions are not allowed within a
class declaration. (See section 4.9 of the standard: Any declaration that
specifies a value is a definition.)

-Howard

[llewelly]

hi******@yahoo. com (Shashidhar Patil) writes:

here is the code

#include<iostre am.h>
#include<math.h >
#include<conio. h>
class legendre
{
private:
int c,b,z,zz,xx,yy, fact;
double a,nt,x,y,aa,fin al,bb,cc;
double sum1=0;
An object is not initialized by a class definition. An object is
initialized by its constructor. So this is wrong.

All of these variables should be initialized by entries in the
mem-initializer list.

See http://www.parashift.com/c++-faq-lit....html#faq-10.6
public:
int factorial(int n)
{
if (n==0)
return 1;
else
{
fact=n*factoria l(n-1);
return fact;
}
}
// legendre();
You need:

legendre()
:c(0),b(0),z(0) ,zz(0),xx(0),yy (0),fact(0)
,a(0),nt(0),x(0 ),y(0),aa(0),fi nal(0),bb(0),cc (0)
,sum1(0) // <- important.
{}

I initialized all of your member variables in the above
mem-initializer list. Any member variables not listed in the
mem-initializer list will be default-initialized (before the
constructor begins). You must decide wether you want your data
members initialized with 0, or default-initialized (with undefined
values).

legendre():sum1 (0) {}

would also be ok, but all of your other data members would be
default-initialized, and have unknown values.

Notice the variables in the mem-initializer list are in the same order
as the variables occur in the class definition above. Data members
are always initialized in the order they are declared in, *not*
the order they appear in the mem-initializer list. Some compilers
will warn if the mem-initializer list is in a different order.
void calculate(int l,int m,double theta)
{
a=(2*l+1)/2;
b=1- m%1;
c=1+ m%1;
zz=factorial(l) ;
xx=factorial(c) ;
yy=factorial(z) ;
bb=factorial(b)/zz;
cc=factorial(c)/zz;
nt=sqrt(a*bb*cc );
for(int q=0; q<=b/2; q++)
{
z=2*l-2*q;
x=z/(factorial(l-q)*factorial(q) );
y=yy/(xx*factorial(z-c));
sum1+=((pow(-1,l+q))*x*y*(po w(cos(theta),b-2*q)));
}

aa=nt*(pow(sin( theta),m)/pow(2,l));
final=aa*sum1;
cout<<"the value of the expression : "<<final<<e ndl;
}
};

[snip]

[Kevin Goodsell]

Shashidhar Patil wrote:

here is the code

#include<iostre am.h>
This is not a standard header. It comes from pre-standard C++, and has
been outdated for about 6 years now. Standard C++ uses <iostream>.
#include<math.h >
Technically still allowed, but deprecated in favor of <cmath>.
#include<conio. h>
This header has never been part of C++.
class legendre
{
private:
int c,b,z,zz,xx,yy, fact;
double a,nt,x,y,aa,fin al,bb,cc;
double sum1=0;
As others have explained, you can't do this.

<snip>

void main()
In the history of C++ (and C), there has never been a time in which
'void' was an acceptable return type for main. main must return int.
{
int l,m;
double theta;
cout<<"enter the values for l, m and theta: "<<endl;
cin>>l>>m>>thet a;
legendre expression;
expression.calc ulate(l,m,theta );
getch();
Not a standard C++ function.
}

-Kevin
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