Multiple Expressions in Switch Statements

[jsta43catrocks]

In C++, my "switch" statement is okay when I ask it do evaluate ONE expression. (My number that I'm evaluating is one of ten single digits; I have ten cases for the ten digits.)

BUT, I have five separate digits to evaluate.

I can't believe that the only solution is to do:

switch (num1)
{
case 0:...
case 9:
}
 
switch(num2)
{
case 0:...
case 9:
}

etc.

Assuming that my question makes sense, how do I evaluate multiple expressions in a switch statement?

[horace1]

not sure about your logic requirements?
are the statements associated with case 0:. case 1: etc the same in all the switch statements. Something like

    if( num1==1 && num2 ==1 && nium3==1 ....)    {.... }
    else
     if( num1==2 && num2 == 2 && nium3==2 ....)    {.... }

[jsta43catrocks]

I have a list of five different numbers (digits).

My switch statement does something different whether the digit == 1 or whether the digit == 2, etc.

I'm doing the switch statement five different times to five different digits.

It's not liking me trying this:

switch (digit1, digit2, digit3, digit4, digit5)
{ 
case 1:...
case9:
}

but that's essentially what I'm trying to do.

Writing out the entire thing five separate times doesn't seem right.

Does this make sense? (the question, that is)

[horace1]

you store the five digits in an array and use a loop

for(i=0;i<5;i++)
  switch (digits[i])
   { 
    case 1:...
    case9:
}

[jsta43catrocks]

Sadly, we can't use arrays for this.

It makes sense, but this is for a project for school, and we haven't gotten that far in the text yet. (and the teacher has yet to talk about them.)

Are there any other options?

you store the five digits in an array and use a loop

for(i=0;i<5;i++)
  switch (digits[i])
   { 
    case 1:...
    case9:
}

[Ganon11]

Is there a way that you can use a loop to evaluate one digit at a time, or do you have to have them stored as you show (digit1, digit2, ..., digit5)?

I'm thinking something like this:

for (int i = 0; i < 5; i++) {
   cin >> digit;
   //Switch statement to evaluate digit
}

[jsta43catrocks]

Sadly, we can't use arrays for this.

It makes sense, but this is for a project for school, and we haven't gotten that far in the text yet. (and the teacher has yet to talk about them.)

Are there any other options?

I've tried converting it all to a large "if...if else" statement, but it's REALLY long because I've got 10 "else's" for each of the 5 digits, so it's 50+ lines long. (UGH!)

[jsta43catrocks]

Each digit is already named (digit1, digit2, etc.), because they're already being converted from being "chars" into "ints."

(They're being read from a file, but "12345" is read as an entire number, so I'm reading them each as characters first -- one at a time -- and then converting them to integers, so then I can work with them.)

In my effort to boil the question down to the simplest elements, some details get lost.

My "if...if else" statements WORK (see other post), but it looks so cumbersome and awkward. I just thought the switch statement would make it easier(?)

Is there a way that you can use a loop to evaluate one digit at a time, or do you have to have them stored as you show (digit1, digit2, ..., digit5)?

I'm thinking something like this:

for (int i = 0; i < 5; i++) {
   cin >> digit;
   //Switch statement to evaluate digit
}

[horace1]

I've tried converting it all to a large "if...if else" statement, but it's REALLY long because I've got 10 "else's" for each of the 5 digits, so it's 50+ lines long. (UGH!)

could you have the switch in a function and call it five times?

[Ganon11]

What exactly are you going to be doing depending on these digits? Depending on what it is, there might be a way to simplify this process.