Forward declaration and embedded classes

[jerome.pouiller]

I'd like to do this:

class foo: public bar::mho {
public:
class mho { };
};

class bar: public foo::mho {
public:
class mho { };
}

Someone have a solution to declare this?

Thanks,

--
Jezz

[Kai-Uwe Bux]

je************* @gmail.com wrote:

I'd like to do this:

class foo: public bar::mho {
public:
class mho { };
};

class bar: public foo::mho {
public:
class mho { };
}

Someone have a solution to declare this?

Why do you insist on mho being a local class? What about:
class foo_mho {};
class bar_mho {};

class foo : public bar_mho {
public:

typedef foo_mho mho;

};

class bar : public foo_mho {
public:

typedef bar_mho mho;

};
Best

Kai-Uwe Bux

[jerome.pouiller]

Kai-Uwe Bux a écrit :

je************* @gmail.com wrote:

I'd like to do this:

class foo: public bar::mho {
public:
class mho { };
};

class bar: public foo::mho {
public:
class mho { };
}

Someone have a solution to declare this?

Why do you insist on mho being a local class? What about:
class foo_mho {};
class bar_mho {};

class foo : public bar_mho {
public:

typedef foo_mho mho;

};

class bar : public foo_mho {
public:

typedef bar_mho mho;

};

Because I'd like to do something like:
template<class TT &f(typename T::mho &arg);

And your solution works fine in this case :-)
Thanks.

[Sylvester Hesp]

<je************ *@gmail.comwrot e in message
news:11******** **************@ 11g2000cwr.goog legroups.com...

Because I'd like to do something like:
template<class TT &f(typename T::mho &arg);

And your solution works fine in this case :-)
Thanks.

Keep in mind the compiler would never be able to deduce the arguments when
such a function is called without explicit template arguments, so Kai-Uwe's
solution even works better in that respect :)

- Sylvester