Number of elements in an enum

[Mark P]

I'm working on a project where I have something like

enum Modes {mode_a, mode_b, ...};

Due to project spec changes, the number of Modes has increased several
times. There are a few places where it's useful to know the number of
image modes (to set the size of bitsets, etc.) Currently I just use a
const int to hold this size:

enum Modes {mode_a, mode_b, mode_c};
const int number_of_modes = 3;

I'm wondering what the style gurus think about this alternative:

enum Modes {mode_a, mode_b, mode_c, mode_sentinel};
const int number_of_modes = mode_sentinel;

The second version requires just a bit less work to maintain, but is it
trying to be too clever? FWIW, the numerical values of the enum
elements are otherwise not used anywhere.

[Rolf Magnus]

Mark P wrote:

I'm working on a project where I have something like

enum Modes {mode_a, mode_b, ...};

Due to project spec changes, the number of Modes has increased several
times. There are a few places where it's useful to know the number of
image modes (to set the size of bitsets, etc.) Currently I just use a
const int to hold this size:

enum Modes {mode_a, mode_b, mode_c};
const int number_of_modes = 3;

I'm wondering what the style gurus think about this alternative:

enum Modes {mode_a, mode_b, mode_c, mode_sentinel};
const int number_of_modes = mode_sentinel;

The second version requires just a bit less work to maintain, but is it
trying to be too clever? FWIW, the numerical values of the enum
elements are otherwise not used anywhere.

An often used way to do this is even:

enum Modes {mode_a, mode_b, mode_c, number_of_modes };

[mlimber]

Mark P wrote:

I'm working on a project where I have something like

enum Modes {mode_a, mode_b, ...};

Due to project spec changes, the number of Modes has increased several
times. There are a few places where it's useful to know the number of
image modes (to set the size of bitsets, etc.) Currently I just use a
const int to hold this size:

enum Modes {mode_a, mode_b, mode_c};
const int number_of_modes = 3;

I'm wondering what the style gurus think about this alternative:

enum Modes {mode_a, mode_b, mode_c, mode_sentinel};
const int number_of_modes = mode_sentinel;

The second version requires just a bit less work to maintain, but is it
trying to be too clever? FWIW, the numerical values of the enum
elements are otherwise not used anywhere.

The only problem with that is that the sentinel is a valid enum, so

void SetMode( Modes );

void Foo()
{
SetMode( mode_sentinel ); // Ok, but probably won't work
}

Enums aren't perfect in any case [the compiler needn't complain about
"(Modes)0xfffff " either], but I prefer this style:

enum Modes
{
mode_min = 0,
mode_a = mode_min,
mode_b,
mode_c,
mode_max = mode_c
};
enum { n_modes = (mode_max - mode_min) + 1 };

void Bar()
{
SetMode( n_modes ); // Compile-time error
}

It also allows one to iterate relatively easily:

for( Modes m = mode_min; m <= mode_max; m = Modes(m+1) )
{
// ...
}

Cheers! --M

[noone]

On Fri, 12 Jan 2007 20:52:59 +0100, Rolf Magnus wrote:

An often used way to do this is even:

enum Modes {mode_a, mode_b, mode_c, number_of_modes };

but does this work when literal values are assigned to the members of the
enumeration, such as when mapping "power of two" bitfields?

[noone]

On Fri, 12 Jan 2007 19:50:42 +0000, Mark P wrote:

I'm working on a project where I have something like

enum Modes {mode_a, mode_b, ...};

Due to project spec changes, the number of Modes has increased several
times. There are a few places where it's useful to know the number of
image modes (to set the size of bitsets, etc.) Currently I just use a
const int to hold this size:

Just the other day a guy I work with asked me a related question about
whether there is an equivalent in C++ of the Pascal ORD() function to
return the element position of an enumeration member. I don't think there
is, if you assign a non-uniform distribution of literal values to the
members of the enumeration in question. Can someone confirm this?

enum modes { a=12, b=27, c=30, d=900};

How do you determine the (position) of (a)?

[Gavin Deane]

noone wrote:

On Fri, 12 Jan 2007 20:52:59 +0100, Rolf Magnus wrote:

An often used way to do this is even:

enum Modes {mode_a, mode_b, mode_c, number_of_modes };

but does this work when literal values are assigned to the members of the
enumeration, such as when mapping "power of two" bitfields?

No. This relies on the default behaviour that the first enumerator has
the numerical value zero and succesive enumerators have their numerical
value increasing by one each time. If you need to assign arbitrary
values to your enumerators, as far as I know there is no way to
programmaticall y determine the total number of enumerators in the enum.

Gavin Deane

[Gavin Deane]

noone wrote:

Just the other day a guy I work with asked me a related question about
whether there is an equivalent in C++ of the Pascal ORD() function to
return the element position of an enumeration member. I don't think there
is, if you assign a non-uniform distribution of literal values to the
members of the enumeration in question. Can someone confirm this?

enum modes { a=12, b=27, c=30, d=900};

How do you determine the (position) of (a)?

You can't. But then, what code can you write that depends on the
position of a?

Gavin Deane

[noone]

On Fri, 12 Jan 2007 16:42:11 -0800, Gavin Deane wrote:

>
noone wrote:

>Just the other day a guy I work with asked me a related question about
whether there is an equivalent in C++ of the Pascal ORD() function to
return the element position of an enumeration member. I don't think
there is, if you assign a non-uniform distribution of literal values to
the members of the enumeration in question. Can someone confirm this?

enum modes { a=12, b=27, c=30, d=900};

How do you determine the (position) of (a)?

You can't. But then, what code can you write that depends on the position
of a?

I tend to agree with you...just wanted more input for the discussion with
my programmer. If you need element position within a predefined set of
values then there are other constructs in the language that can retrieve
that information.

I really think that enums as a feature of C++ are of limited utility and
don't use them often. I think that wrapping the functionality of enum
in a container class adds a lot more flexibility on the long run....yeah,
I know, dereferencing an object member/value is generally a heavier
process than referencing an enum element. :^)

I know that from an early age the comp sci professors beat enumerated
types into our heads, but other than as a (human readable abstraction) I
don't see much utility that can't be emulated by other means...

But I suppose we could degenerate this into an argument over whether
abstract data types are necessary since they all degenerate to list or
array processing in system memory.

Smiles

[Martin Willers]

Gavin Deane wrote:

An often used way to do this is even:

enum Modes {mode_a, mode_b, mode_c, number_of_modes };

but does this work when literal values are assigned to the members of the
enumeration, such as when mapping "power of two" bitfields?

No. This relies on the default behaviour that the first enumerator has
the numerical value zero and succesive enumerators have their numerical
value increasing by one each time. If you need to assign arbitrary
values to your enumerators, as far as I know there is no way to
programmaticall y determine the total number of enumerators in the enum.

In case anyone is interested, I've implemented such a check a while ago
for some project of mine where knowing this was very important. (Actually,
I needed a minor variant of this check, where every enum value had to be
present in some array.)
My check is based on the idea of Duff's device and depends on the compiler
giving a warning if some value of the enum is not handled in a "switch".
It then goes like this:

enum eOption { OPT_FOO, OPT_BAR, OPT_BAZ, OPT_XXX };

static void check_enum(enum eOption opt)
{
int count = 0;
int first = 0;
int i = 0;
switch (opt) {
do {
default:
case OPT_FOO: count += 1;
case OPT_BAR: count += 1;
case OPT_BAZ: count += 1;
case OPT_XXX: count += 1;
if (first == 0)
first = count;
} while (++i < 2);
}
int num = count - first;
printf("This enum has %d entries.\n", num);
}

You have to specify every value of the enum in the switch, but you get
warned by the compiler (use -Wswitch-enum in the case of gcc) if you forgot
one.
I believe this to be safe to use in all circumstances:
- You can reorder the 'case's as you like. (That's why the switch is run
twice.)
- You need not even pass a valid enum value to check_enum().
Any value will do. (The placement of 'default' takes care of that.)

Since enums are static data, you only need to do this check once on program
startup. Of course, if the enum has a lot of entries, you have to do a lot
of typing...

Martin Willers