I'm thinking about using a function tamplate to verify that an
identifier is of an array type. May the following template be
used for this purpose:
template< typename T, int N >
void check_array( T(&)[N] )
{
}
And what about using size_t instead of int?
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Angel Tsankov wrote:
I'm thinking about using a function tamplate to verify that an
identifier is of an array type. May the following template be
used for this purpose:
template< typename T, int N >
void check_array( T(&)[N] )
{
}
And what about using size_t instead of int?
Yes, I'd probably use 'size_t', although 'int' would work almost
as well if the size is less than INT_MAX.
Perhaps incorporating this with a compile-time assert would be
a bit better, and you could try incorporating a decent error
message into it, but should work right out of the box...
Why do you ask? Have you run into any problem with it?
V
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Angel Tsankov schrieb:
I'm thinking about using a function tamplate to verify that an
identifier is of an array type. May the following template be
used for this purpose:
template< typename T, int N >
void check_array( T(&)[N] )
{
}
Yes, absolutely.
And what about using size_t instead of int?
Indeed size_t is the canonical type for this approach, because it is
unsigned and because every statically creatable array must have a
size expressable via sizeof, which itself returns size_t.
Greetings from Bremen,
Daniel Krügler
--
[ See http://www.gotw.ca/resources/clcm.htm for info about ]
[ comp.lang.c++.m oderated. First time posters: Do this! ]
>[ I dropped cross-posting in c.l.c++.m so the articles appear
>sooner]
Angel Tsankov wrote:
>I'm thinking about using a function tamplate to verify that an identifier is of an array type. May the following template be used for this purpose:
template< typename T, int N > void check_array( T(&)[N] ) { }
And what about using size_t instead of int?
Yes, I'd probably use 'size_t', although 'int' would work
almost
as well if the size is less than INT_MAX.
Perhaps incorporating this with a compile-time assert would be
a bit better,
What is your idea?
and you could try incorporating a decent error
message into it, but should work right out of the box...
Is there a standard way to incorporate an error message?
Why do you ask? Have you run into any problem with it?
No, I have not found any problems with it. I am just curious if
it is reliable, that is whether the template shall be implicitly
instantiated if and only if the argument is of an array type.
Angel Tsankov wrote:
>[ I dropped cross-posting in c.l.c++.m so the articles appear sooner]
Angel Tsankov wrote:
>>I'm thinking about using a function tamplate to verify that an identifier is of an array type. May the following template be used for this purpose:
template< typename T, int N > void check_array( T(&)[N] ) { }
And what about using size_t instead of int?
Yes, I'd probably use 'size_t', although 'int' would work almost as well if the size is less than INT_MAX.
Perhaps incorporating this with a compile-time assert would be a bit better,
What is your idea?
Check out Boost's compile-time assertions based on templates.
They have a whole bunch of them, IIRC.
>and you could try incorporating a decent error message into it, but should work right out of the box...
Is there a standard way to incorporate an error message?
No. And it's not a simple task either. If you call your function
'check_array', and it fails, what error message do you see? Would
naming 'check_array' differently clarify it? You could try using
SFINAE mechanism to even cause something like "not an array" from
your particular compiler, I bet.
>Why do you ask? Have you run into any problem with it?
No, I have not found any problems with it. I am just curious if
it is reliable, that is whether the template shall be implicitly
instantiated if and only if the argument is of an array type.
Yes, that's certaintly so.
V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask
Angel Tsankov wrote:
I'm thinking about using a function tamplate to verify that an
identifier is of an array type. May the following template be used for
this purpose:
template< typename T, int N >
void check_array( T(&)[N] )
{
}
The only change I would consider is making it so it can be used statically.
e.g.
template< typename T, unsigned N >
char (check_array_he lper( T(&)[N] ))[N];
#define check_array(X) (sizeof check_array_hel per(X) )
Perhaps you could eliminate the marco using somthing like this.
template< typename T>
struct check_array;
template< typename T, unsigned N >
struct check_array< T(&)[N] >
{
static const bool is_array = true;
};
Now you can use somthing like this:
check_array<var >::is_array
>
And what about using size_t instead of int?
Use size_t.
>I'm thinking about using a function tamplate to verify that an
>identifier is of an array type. May the following template be used for this purpose:
template< typename T, int N > void check_array( T(&)[N] ) { }
The only change I would consider is making it so it can be used
statically.
e.g.
template< typename T, unsigned N >
char (check_array_he lper( T(&)[N] ))[N];
#define check_array(X) (sizeof check_array_hel per(X) )
Perhaps you could eliminate the marco using somthing like this.
template< typename T>
struct check_array;
template< typename T, unsigned N >
struct check_array< T(&)[N] >
{
static const bool is_array = true;
};
Now you can use somthing like this:
check_array<var >::is_array
Well, one may only specify a typename or an integer as a template
argument. In fact, this is the basic difference between class
templates and function templates - function template parameters
may be deduced from the arguments to the function. Class template
parameters however, may not be deduced.
Angel Tsankov wrote:
I'm thinking about using a function tamplate to verify that an
identifier is of an array type. May the following template be
used for this purpose:
template< typename T, int N >
void check_array( T(&)[N] )
{
}
How do you envision using the check_array() function template to a test
for an array type exactly? If anything, std::tr1::is_ar ray (or
std::is_array in the future) is pretty easy to use:
#include <tr1/type_traits>
char a[30];
using std::tr1::is_ar ray;
static bool b = is_array<a>::va lue;
Greg
Angel Tsankov wrote:
....
>Now you can use somthing like this: check_array<va r>::is_array
Well, one may only specify a typename or an integer as a template
argument. In fact, this is the basic difference between class templates
and function templates - function template parameters may be deduced
from the arguments to the function. Class template parameters however,
may not be deduced.
Yep - I don't know what I was thinking...
Greg wrote:
Angel Tsankov wrote:
>I'm thinking about using a function tamplate to verify that an identifier is of an array type. May the following template be used for this purpose:
template< typename T, int N > void check_array( T(&)[N] ) { }
How do you envision using the check_array() function template to a test
for an array type exactly? If anything, std::tr1::is_ar ray (or
std::is_array in the future) is pretty easy to use:
#include <tr1/type_traits>
char a[30];
using std::tr1::is_ar ray;
static bool b = is_array<a>::va lue;
Greg
Only works for variables with external linkage. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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