"Forward maximum match" mean that there is a dictionary contains
thousands of items which are single words. For example, "kid", "nice",
"best"...
And here get a string "kidnicebs" , the forward maximum match algorithm
need to find the longest string that matches the string in dictionary.
Because the longest string in the dictionary has a length of 4, so the
algoritm pick the first four characters of the string(that's why it's
called forward):
kidn-------not find in dictionary
then, first three: kid --------find in dictionay
then kid is picked out as a segment, then the algorithm continue with
"nicebs"...
I'm wondering is there any fast algorithm to deal with this demand,
what kind of data structure should I use? Thanks for helping me. 1 2593 hn********@gmai l.com wrote:
"Forward maximum match" mean that there is a dictionary contains
thousands of items which are single words. For example, "kid", "nice",
"best"...
And here get a string "kidnicebs" , the forward maximum match algorithm
need to find the longest string that matches the string in dictionary.
Because the longest string in the dictionary has a length of 4, so the
algoritm pick the first four characters of the string(that's why it's
called forward):
kidn-------not find in dictionary
then, first three: kid --------find in dictionay
then kid is picked out as a segment, then the algorithm continue with
"nicebs"...
I'm wondering is there any fast algorithm to deal with this demand,
what kind of data structure should I use? Thanks for helping me.
Firstly, don't multi-post to c.l.c++ and c.l.c++.m. You're off topic
for both. Posting to comp.programmin g and setting followup to same.
You can do it with having to examine each character in the input
string only once. There may be a temptation to try to exploit some
sort of skip ahead based on the length of the longest string found
so far but I suspect that number of potential target words nullifies
any advantage of skip ahead since it's likely to only be 1. I'll
let others have fun with this.
btw, this isn't a homework problem, is it?
--
Joe Seigh
When you get lemons, you make lemonade.
When you get hardware, you make software. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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--
Alex Vinokur
email: alex DOT vinokur AT gmail DOT com
http://mathforum.org/library/view/10978.html
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