if-else statement

[bitong]

Just cant figure out how to formulate the correct syntax..I can do it in looping statement but my professor said that use only the simple if-else statement. The problem goes like this..Write a program that will determine if the number that you entered is either odd or even number..

I tried writing this code..

#include<stdio. h>
main()
{
int nos;
clrscr();
printf("Enter number:");
scanf("%d",&nos );
if(nos++){
printf("Odd number");
}
else {
printf("Even number");
}
getch();
}

[ssharish]

this is the simple way of finding odd or even

 
if(num % 2 == 0)
    printf("Even\n");
else
  printf("Odd\n");
 
 

there are many different ways of finding odd and even. Depends upon the complexity of your program

main should return value, Have a look at this main

int main()
{
   ---
   ---
   return 0;
}
 

by the way use code tags

ssharish

[bitong]

this is the simple way of finding odd or even

 
if(num % 2 == 0)
    printf("Even\n");
else
  printf("Odd\n");
 
 

there are many different ways of finding odd and even. Depends upon the complexity of your program

main should return value, Have a look at this main

int main()
{
   ---
   ---
   return 0;
}
 

by the way use code tags

ssharish

[quote=bitong]hello...i tried the code that you gave but still it didn't work..

[code]

#include<stdio. h>
int main()
{
int nos;
printf("Enter number:");
scanf("&d",&nos );
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

[DeMan]

In your scanf function you have an & instead of a %

it should be: scanf("%d",&nos );

[bitong]

In your scanf function you have an & instead of a %

it should be: scanf("%d",&nos );

sori...typo error... =)

#include<stdio. h>
int main()
{
int nos;
printf("Enter number:");
scanf("%d",&nos );
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

even though the code goes like that, still any number that I input it brings back the "Even Number" output...even if i entered 3 or 2....

=)

[sivadhas2006]

sori...typo error... =)

#include<stdio. h>
int main()
{
int nos;
printf("Enter number:");
scanf("%d",&nos );
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

even though the code goes like that, still any number that I input it brings back the "Even Number" output...even if i entered 3 or 2....

=)

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

[DeMan]

In your print satement, you could add (temporarily of course) a printout of what the number is which might give a clue.

printf("Even Number %d", nos);

Given that it is coming even I would suspect that it is coming through 0, however I must admit the code worked for me.

[bitong]

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

Tnx M.Sivadhas...it worked!! =)

[bitong]

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

just want to ask whats the function or the purpose of placing % in the "if" statement ---> if(nos % 2 == 0)?

[MariyaGel]

just want to ask whats the function or the purpose of placing % in the "if" statement ---> if(nos % 2 == 0)?

The purpose of placing the % is that ur asking for the remainder after the number is divided by 2. If the remainder is 0 then the number is even. e.g if you do 10 % 6 than that would give you 4.
Hope it helped