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Smart Pointer release() const : it can set the pointer to null with the keyword "const"?


In Smart Pointer class, we have a piece of code:

inline void release(void) const { if (mPtr) mPtr->release(); mPtr = 0;
}

It can set mPtr but it is still const?

Why could this work and why it can be compiled? We have used it for
years.

Thanks.

- C.

Sep 6 '06 #1
1 1858
coala wrote:
In Smart Pointer class, we have a piece of code:
[..]
You already asked that, three hours ago. Is there something you
didn't understand in the answers given? Do you not know how to
see the responses you've got so far? (if so, fat chance getting
this this question to be answered...)

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask
Sep 6 '06 #2

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