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Value bits as compile-time constant!

Over on comp.lang.c, Hallvard B Furuseth devised a compile-time constant
representing the amount of value representation bits in an unsigned
integer type. In true C fashion, here it is as a macro:
/* Number of bits in inttype_MAX, or in any (1<<k)-1 where 0 <= k < 3.2E+
10 */
#define IMAX_BITS(m) ((m) /((m)%0x3fffffff L+1) /0x3fffffffL %0x3fffffffL
*30 \
+ (m)%0x3fffffffL /((m)%31+1)/31%31*5 + 4-12/((m)%
31+3))
You supply it with an unsigned integer value whose bit-pattern consists
of all 1's, e.g.:

1 (Decimal: 1)
11 (Decimal: 3)
111 (Decimal: 7)
11111111 (Decimal: 255)
To find out the amount of value bits in an unsigned integer type, you
supply it with that type's max value (i.e. a bit pattern of all 1's). The
handiest way to get the max value of an unsigned integer type is to
assign -1 to it:

unsigned const max_value = -1;

unsigned const amount_value_bi ts = IMAX_BITS( max_value );
Here's some template code I've written which makes use of it:
template<class T>
struct IMaxBits {

template<T m>
struct AllOnes {

static unsigned const val =
m /(m%0x3fffffffL+ 1) /0x3fffffffL %0x3fffffffL *30
+ m%0x3fffffffL /(m%31+1)/31%31*5 + 4-12/(m%31+3);

};

};
template<class T>
struct AmountValueBits {

static unsigned const val = IMaxBits<T>::te mplate AllOnes<-1>::val;

};
#include <cstdlib>
#include <cstring>
#include <cstddef>
#include <cassert>

template<std::s ize_t width>
inline const char* CenterHoriz( const char * const p )
{
using std::memset;
using std::strlen;
using std::size_t;

static char spaces[width + 1];
memset( spaces, ' ', width );

size_t const len = strlen( p );

assert( width >= len );
char * const pos = spaces + ( width / 2 - len / 2 );
memcpy( pos, p, len );

return spaces;
}

#include <iostream>

extern char const str_uchar[] = "unsigned char";
extern char const str_ushort[] = "unsigned short";
extern char const str_uint[] = "unsigned int";
extern char const str_ulong[] = "unsigned long";

template<class T, const char* str>
void PrintRow()
{
using std::cout;

unsigned const total_bits = sizeof(T) * AmountValueBits <unsigned
char>::val;
unsigned const val_bits = AmountValueBits <T>::val;
unsigned const pad_bits = total_bits - val_bits;

const char * const spaces_val =
val_bits > 99 ? "" : ( val_bits > 9 ? " " : " " );

const char * const spaces_pad =
pad_bits > 99 ? "" : ( pad_bits > 9 ? " " : " " );

const char * const spaces_total =
total_bits > 99 ? "" : ( total_bits > 9 ? " " : " " );
cout << "||" << CenterHoriz<21> (str) << "|| "
<< spaces_val << val_bits << " || " << spaces_pad <<
pad_bits
<< " || " << spaces_total << total_bits << " ||\n"

"---------------------------------------------------------------------
\n";
}

int main()
{
using std::cout;

cout <<

"
=============== =============== =============== =\n"
" || Value bits || Padding Bits || Total Bits
||\n"

"============== =============== =============== =============== ==========
\n";

PrintRow<unsign ed char, str_uchar>();
PrintRow<unsign ed short, str_ushort>();
PrintRow<unsign ed, str_uint>();
PrintRow<unsign ed long, str_ulong>();

cout << "\n\n\n";

std::system( "PAUSE" );
}

I'd be interested to hear if anyone gets some "interestin g" values.

--

Frederick Gotham
Jun 25 '06
12 2263
* Jerry Coffin:

I've seen a compiler for a 12-bit DSP that stored char as 8
significant bits with 4 padding bits.


That would be a non-conforming compiler. For char all bits participate
in the value representation. Per the standard.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Jun 26 '06 #11
In article <4g************ *@individual.ne t>, al***@start.no says...
* Jerry Coffin:

I've seen a compiler for a 12-bit DSP that stored char as 8
significant bits with 4 padding bits.


That would be a non-conforming compiler. For char all bits participate
in the value representation. Per the standard.


I should have pointed out that this was a C (89/90) compiler, which
didn't have that requirement, if memory serves. OTOH, I'm not sure
how conforming code could see the difference, so it might still be
able to sneak in under the as-if rule.

--
Later,
Jerry.

The universe is a figment of its own imagination.
Jun 26 '06 #12
Jerry Coffin posted:
In article <4g************ *@individual.ne t>, al***@start.no says...
* Jerry Coffin:
>
> I've seen a compiler for a 12-bit DSP that stored char as 8
> significant bits with 4 padding bits.


That would be a non-conforming compiler. For char all bits participate in the value representation. Per the standard.


I should have pointed out that this was a C (89/90) compiler, which
didn't have that requirement, if memory serves. OTOH, I'm not sure
how conforming code could see the difference, so it might still be
able to sneak in under the as-if rule.

In C++, only the following three types are guaranteed to contain no
padding:

char
signed char
unsigned char
In C, only the following type is guaranteed to contain no padding:

unsigned char
--

Frederick Gotham
Jun 26 '06 #13

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