std::ostringstr eam

[bob]

For reasons that are irrelevant , we cannot use sprintf to do
conversions between doubles, ints etc. to char*. We're using the
std::ostringstr eam type. Basically we have a function that takes a
double and needs to store a string representation of it into a vector
of strings. ...
something like this;

void pussy::(const double d)
{
std::ostringstr eam strm;
strm << d;

stringbuf *pbuf = strm.rdbuf();
_vect[some_index] = pbuf->str();

}

however this code involves taking a copy of the contents of pbuf string
and I'd like to avoid that. Is there a more efficient way of achieving
my goal without using sprintf etc.
thanks

G

[Daniel T.]

In article <11************ **********@g43g 2000cwa.googleg roups.com>,
"bo*@blah.c om" <Gr**********@g mail.com> wrote:

For reasons that are irrelevant , we cannot use sprintf to do
conversions between doubles, ints etc. to char*. We're using the
std::ostringstr eam type. Basically we have a function that takes a
double and needs to store a string representation of it into a vector
of strings. ...
something like this;

void pussy::(const double d)
{
std::ostringstr eam strm;
strm << d;

stringbuf *pbuf = strm.rdbuf();
_vect[some_index] = pbuf->str();

}

however this code involves taking a copy of the contents of pbuf string
and I'd like to avoid that. Is there a more efficient way of achieving
my goal without using sprintf etc.
thanks

Have you looked into boost.org "lexical_ca st"? I personally feel that it
is the best (it even looks like a standard C++ cast.)

string s = lexical_cast<st ring>( myDouble );

Below is a naive implementation of it, I expect that Boost's full
implementation is faster.

template < typename Result, Input >
Result lexical_cast( Input in ) {
stringstream ss;
Result result;
if ( !( ss << in && ss >> result ) ) throw std::bad_cast() ;
return result;
}
--
Magic depends on tradition and belief. It does not welcome observation,
nor does it profit by experiment. On the other hand, science is based
on experience; it is open to correction by observation and experiment.

[bob]

Genius! I've been looking for a reason to use boost for a while
now....this is ideal. :)

cheers mate,

G