There was a way to trinck program to call purly abstract non-existing
method (causing undefined behaviour), I would like to try that for
curiosity (how different compilers/platforms react), how to do it? 7 2817
if Class A is an ABC you can invoke A->f() such that f() is a pure
virtual from A's destructor
> Rafał Maj Raf256wrote:
There was a way to trinck program to call purly abstract
non-existing method (causing undefined behaviour), I would like to try that for curiosity (how different compilers/platforms react), how to do it?
namespace
{
class Base
{
public:
virtual void doSomething() = 0;
void test()
{
doSomething();
}
};
class Sily : public Base
{
public:
Sily() { test(); }
virtual ~Sily() { }
};
class Derived : public Sily
{
public:
Derived() { doSomething(); }
virtual ~Derived() { }
virtual void doSomething()
{
}
};
}
int main()
{
Derived();
return 0;
}
Rafał Maj Raf256 wrote: There was a way to trinck program to call purly abstract non-existing method (causing undefined behaviour), I would like to try that for curiosity (how different compilers/platforms react), how to do it?
Try qualifying the name with the class it's in:
object.ABC::fun ction(params);
I don't understand the purpose, though. What knowledge are you going
to derive from that "exercise"?
V
--
Please remove capital As from my address when replying by mail
Victor Bazarov wrote: Try qualifying the name with the class it's in:
object.ABC::fun ction(params);
I don't understand the purpose, though. What knowledge are you going to derive from that "exercise"?
I tried to just this and it turns out that at least gcc catches this
attempt at link time: it issues an unresolved symbol error for
'ABC::function( )'. What works actually involves three classes:
struct base
{
virtual ~base() {}
virtual void f() = 0;
void call() { this->f(); }
};
struct aux: base { aux() { this->call(); } };
struct derived: aux { void f() {} };
int main() { derived obj; }
--
<mailto:di***** ******@yahoo.co m> <http://www.dietmar-kuehl.de/>
<http://www.eai-systems.com> - Efficient Artificial Intelligence
> JetSnaiLwrote:
[quote:22d7f86ef e="Rafał Maj Raf256"]There was a way to trinck
program to call purly abstract non-existing method (causing undefined behaviour), I would like to try that for curiosity (how different compilers/platforms react), how to do it?
namespace
{
class Base
{
public:
virtual void doSomething() = 0;
void test()
{
doSomething();
}
};
class Sily : public Base
{
public:
Sily() { test(); }
virtual ~Sily() { }
};
class Derived : public Sily
{
public:
Derived() { doSomething(); }
virtual ~Derived() { }
virtual void doSomething()
{
}
};
}
int main()
{
Derived();
return 0;
}
[/quote:22d7f86ef e]
Hey, guys. The code I provide works with MS Visual Studio 6, 7.0 and
7.1 compilers. I think it will work with gcc and others too.
Dietmar Kuehl wrote:
What works actually involves three classes: struct base { virtual ~base() {} virtual void f() = 0; void call() { this->f(); } };
struct aux: base { aux() { this->call(); } }; struct derived: aux { void f() {} };
int main() { derived obj; }
I believe your goal is to call a purely abstract function (in other
words f() in 'base')?
That isn't successfully calling a non-existant function. "derived" has
an f. Therefor the call to f() within derived's immediate parent is
calling an existing function...it is calling derived's version of f().
To prove this place 'cerr << "THIS IS DERIVED'S F().";' in derived's
version of f().
So long as you are not in a constructor virtual calls go to the most
derived definition. In aux 'this' is a pointer to an aux but the very
definition of a virtual function means that a call to f() through that
pointer still resolves to the definition in 'derived'. Inside of
constructors this is undefined I believe and, though the virtual
mechanism might still work, your derived class is not fully constructed
(construction is top->down basically) so the very likely result is an
explosion.
roberts.n...@gm ail.com wrote: Dietmar Kuehl wrote: What works actually involves three classes: struct base { virtual ~base() {} virtual void f() = 0; void call() { this->f(); } };
struct aux: base { aux() { this->call(); } }; struct derived: aux { void f() {} };
int main() { derived obj; } I believe your goal is to call a purely abstract function (in other words f() in 'base')?
That isn't successfully calling a non-existant function. "derived" has an f. Therefor the call to f() within derived's immediate parent is calling an existing function...it is calling derived's version of f(). To prove this place 'cerr << "THIS IS DERIVED'S F().";' in derived's version of f().
Nevermind that, you are in a constructor...t he result is undefined I
think though doesn't necessarily call the abstract function. That's
why I make class names capitalized. So long as you are not in a constructor virtual calls go to the most derived definition. In aux 'this' is a pointer to an aux but the very definition of a virtual function means that a call to f() through that pointer still resolves to the definition in 'derived'. Inside of constructors this is undefined I believe and, though the virtual mechanism might still work, your derived class is not fully constructed (construction is top->down basically) so the very likely result is an explosion. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
by: Hubert Baumeister |
last post by:
Fifth International Conference on
eXtreme Programming and Agile Processes
in Software Engineering
XP2004
June 6-10, 2004, Garmisch-Partenkirchen, Germany
http://www.xp2004.org/
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Hi,
Given a collection of similar but not exact entities (or products)
Toyota, Ford, Buick, etc; I am contemplating using the Abstraction pattern
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This is a technical C++ post regarding the
Microsoft runtime error R6025 Pure Virtual Function Call
that sometime occurs in programs compiled with
Microsoft Visual C++ 6.0.
Please consider the following simple illegal C++ program:
class Listener {
public:
virtual void onEvent(int n) = 0;
|
by: Paul Bilnoski |
last post by:
Can someone explain why a call to a virtual function within a
constructor is illegal?
The class can't be instantiated because functions are abstract, so
whatever extends it implements them which means they should be
implemented when the constructor for the base is called.
Is it because the base gets constructed before the rest of the object
and the vftable doesn't exist?
I think something like this works in Java.
class AbstractBase
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Hello all,
I'm very new to C but I have a number of years of Common Lisp programming
experience. I'm trying to figure out ways of translating higher order
concepts such as closures into C. The code will not be idiomatic C.
GCC has an extension to ISO C that permits nested functions:
<http://gcc.gnu.org/onlinedocs/gcc/Nested-Functions.html>
For implementing closures they have a serious limitation:
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Hi all,
A shameless plug and reminder for EuroPython 2006 (July 3-5):
* you can submit talk proposals until May 31st.
* there is a refereed papers track; deadline for abstracts: May 5th.
See the full call for papers below.
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Hi all,
He're a reminder to submit a talk at EuroPython!
Like each year, we have both the regular conference (see call at
http://indico.cern.ch/conferenceCFA.py?confId=13919) and a somewhat
separated Refereed Papers section. Here is the call for the latter.
The deadline for both is the 18th of May.
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