Hi,
Having not done any C programming for a while I am trying to get back into
it by converting an old java assignment into C.
The problem is I am getting a segmentation fault at runtime which I am
having trouble fixing(program below)
The idea of the program is to convert input(integers) into words eg:
# 101
returns
#one hundred one
I have found the problem is with the strcat of the strings & literals --
tried redef
strcat to allow for enough memory--
#define STRCAT(d,s) d=( char *)malloc(d, strlen(d)+strle n(s)+1);strcat( d,s)
then replaced strcat with STRCAT but end up with more errors? Also tried
using a buffer with enough memory and strcat to that - doesn't seem to work
either.
Not sure how to fix it from here.
Any help appreciated, regards
Ian
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define STRCAT(d,s) d=( char *)malloc(d, strlen(d)+strle n(s)+1);strcat( d,s)
char* convertLessThan OneThousand(int number);
char* convert(int number);
static int num;
static char *numNames[] = {
"",
" one",
" two",
" three",
" four",
" five",
" six",
" seven",
" eight",
" nine",
" ten",
" eleven",
" twelve",
" thirteen",
" fourteen",
" fifteen",
" sixteen",
" seventeen",
" eighteen",
" nineteen"
};
static char *tensNames[] = {
"",
" ten",
" twenty",
" thirty",
" fourty",
" fifty",
" sixty",
" seventy",
" eighty",
" ninety"
};
char *majorNames[] = {
"",
" thousand",
" million",
" billion",
" trillion",
" quadrillion",
" quintillion"
};
int main(){
printf("integer to convert: ");
scanf("%d", &num);
printf("convert ed to words: %s\n", convert(num));
return 0;
}
char* convertLessThan OneThousand(int number) {
char* soFar;
/*char buffer[10000];
char* soFar;
soFar = buffer;*/
char* hundred = "hundred";
if (number % 100 < 20){
soFar = numNames[number % 100];
number /= 100;
}
else {
soFar = numNames[number % 10];
number /= 10;
soFar = strcat(tensName s[number % 10], soFar);
number /= 10;
}
if (number == 0)
return soFar;
/*return numNames[number] + " hundred" + soFar;*/
return strcat(numNames[number], strcat(hundred, soFar));
}
char* convert(int number) {
char* zero = "zero";
if (number == 0) {
return zero; }
char* prefix = "";
/*if (number < 0) {
number = -number;
prefix = "negative";
}*/
char* soFar = "";
int place = 0;
do {
int n = number % 1000;
if (n != 0){
char* s = convertLessThan OneThousand(n);
/*soFar = s + majorNames[place] + soFar;*/
soFar = strcat(s, strcat(majorNam es[place], soFar));
}
place++;
number /= 1000;
} while (number > 0);
/*return (prefix + soFar).trim();*/
return (strcat(prefix, soFar));
} 5 4643
Ian Stanley wrote [almost exactly what he wrote in
alt.comp.lang.l earn.c-c++]
Did you read my reply in the other group? You're using strcat() to
append to string literals. It doesn't work. You can't change
literals.
BTW, it's "forty", not "fourty".
--
Tom Zych
This email address will expire at some point to thwart spammers.
Permanent address: echo 'g******@cbobk. pbz' | rot13
Tom Zych wrote: Ian Stanley wrote [almost exactly what he wrote in alt.comp.lang.l earn.c-c++]
Did you read my reply in the other group? You're using strcat() to append to string literals. It doesn't work. You can't change literals.
BTW, it's "forty", not "fourty".
Yes, but it's only a spilling error. :-)
--
Joe Wright mailto:jo****** **@earthlink.ne t
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---
Joe Wright <jo********@ear thlink.net> wrote in message news:<3F******* ****@earthlink. net>... Tom Zych wrote: Ian Stanley wrote [almost exactly what he wrote in alt.comp.lang.l earn.c-c++]
Did you read my reply in the other group? You're using strcat() to append to string literals. It doesn't work. You can't change literals.
BTW, it's "forty", not "fourty".
Yes, but it's only a spilling error. :-)
Thanks Tom,
Is there a way to fix it?
I have never used sprintf before- are there any good examples out there?
Thanks again for your reply
Ian
Ian wrote: Is there a way to fix it? I have never used sprintf before- are there any good examples out there?
It's just like printf except the output goes into a string instead
of to stdout. So it's handy for building up a string from other
strings:
char a[] = "Like ";
char b[] = "this, ";
char c[] = "see?";
char result[30];
sprintf(result, "%s%s%s", a, b, c);
// check return value
--
Tom Zych
This email address will expire at some point to thwart spammers.
Permanent address: echo 'g******@cbobk. pbz' | rot13
Tom Zych <tz******@pobox .com> wrote: Ian wrote:
Is there a way to fix it? I have never used sprintf before- are there any good examples out there?
It's just like printf except the output goes into a string instead of to stdout. So it's handy for building up a string from other strings:
char a[] = "Like "; char b[] = "this, "; char c[] = "see?"; char result[30];
sprintf(result , "%s%s%s", a, b, c); // check return value
My two cents: make sure that 'result' is big enough to hold the
resulting string to protect against buffer overrun.
In C99 one could use snprintf() which takes the size of the buffer
as an additional argument.
Irrwahn
--
do not write: void main(...)
do not use gets()
do not cast the return value of malloc()
do not fflush( stdin )
read the c.l.c-faq: http://www.eskimo.com/~scs/C-faq/top.html This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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