Having problem on printing a string using printf?

[jt]

Here is my code below, it doesn't printf. But I step it thru using the for
statement and use putchar to the display, its there...

How can I get it to use printf? If the problem is needing a null at the end
and how can I do this?
I tried pos='\0' after my last memcpy and that doesn't work either.
=============== =============== =============== =============== =

void ERR(char * err_msg){

char tmp[1024],*pos;
unsigned int len,i,s;

memset(tmp,'\0' ,1024);

len=strlen(err_ msg);
s = ntohl(len);

pos=tmp;
memcpy(pos,&s,s izeof(s));
pos+=sizeof(s);
memcpy(pos,err_ msg,len);

printf("%s\n",t mp);

}

[Eric Sosman]

jt wrote:

void ERR(const char *err_msg)
{
printf("%2x %s\n", (unsigned long)strlen(err _msg), err_msg);
{

That is good, but we are not quite there of what I need to accomplish.

This is what printf prints: 2Athis is a test for the err messages to cad
(that good and we are getting somewhere not)

The client will read it in binary hex and you see that the 1st 4 bytes (32
61): 32 61 74 68 78 20 and so on .... would be a very large decimal.

note: my requirement is that fist four bytes should be in network byte order
and read as 00 2A ..... in binary hex. Not ascii as above.

I tried everything and it always comes out in ascii as you have it as well.

You need something like this:

unsigned long len = strlen(err_msg) ;
printf ("%c%c%c%c%s ",
(int)(len >> 24),
(int)((len >> 16) & 0xFF),
(int)((len >> 8) & 0xFF),
(int)(len & 0xFF),
err_msg);

--
Eric Sosman
es*****@acm-dot-org.invalid

[Dave Thompson]

On Sun, 12 Jun 2005 07:01:31 GMT, Martin Ambuhl
<ma*****@earthl ink.net> wrote:

jt wrote:

s = ntohl(len);

ntohl is not a standard C function (which makes it off-topic here); it
isn't even a standard POSIX function (which makes it off-topic in even
more places). <snip>

It is POSIX now, as of 2001/2002 = SUS3. Still not standard C.

- David.Thompson1 at worldnet.att.ne t