using setjmp

[JS]

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?
struct pcb {
void *(*start_routin e) (void *);
void *arg;
jmp_buf state;
int stack[1024];
};
struct pcb *pcb_pointer;
pcb_pointer = (struct pcb *) malloc(sizeof(s truct pcb));
if(setjmp(pcb_p ointer->state)) {
current->start_routine( current->arg);
printf("Thread returned\n");
exit(0);
}

[Gordon Burditt]

>When setjmp is called how can the if statement evaluate to true or false

when setjmp only returns 0 or non-zero?

There is no true or false in C89. if statements execute the "then" clause
(even though there's no "then" keyword) if the condition evaluates to
non-zero.

While C99 has true and false, this has nothing to do with if statements.

Gordon L. Burditt

[Dave Vandervies]

In article <d1**********@n ews.net.uni-c.dk>, JS <[e-mail] m> wrote:

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?
Have a coffee, go outside, and sit under a tree (or, if the weather
fails to be cooperative, at least get away from the computer), and
contemplate the difference between true/false and nonzero/zero, and you
will be enlightened.
dave

--
Dave Vandervies dj******@csclub .uwaterloo.caThe Kremlin has a mother these days?

After a fflush(stdin), it might end up having three mothers.
--Joona I Palaste and Gordon Burditt in comp.lang.c

[JS]

"Dave Vandervies" <dj******@csclu b.uwaterloo.ca> skrev i en meddelelse
news:d1******** **@rumours.uwat erloo.ca...

In article <d1**********@n ews.net.uni-c.dk>, JS <[e-mail] m> wrote:

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?

Have a coffee, go outside, and sit under a tree (or, if the weather
fails to be cooperative, at least get away from the computer), and
contemplate the difference between true/false and nonzero/zero, and you
will be enlightened.

Well I have only Java experience and not yet found anything about this
definition in K&R.

[JS]

"Gordon Burditt" <go****@hammy.b urditt.org> skrev i en meddelelse
news:42******** **************@ news.airnews.ne t...

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?

There is no true or false in C89. if statements execute the "then" clause
(even though there's no "then" keyword) if the condition evaluates to
non-zero.

While C99 has true and false, this has nothing to do with if statements.

Gordon L. Burditt

Where can I find C89 and C99??

[Mark Odell]

JS wrote:

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?

Have a coffee, go outside, and sit under a tree (or, if the weather
fails to be cooperative, at least get away from the computer), and
contemplate the difference between true/false and nonzero/zero, and you
will be enlightened.

Well I have only Java experience and not yet found anything about this
definition in K&R.

I have found that 0 (zero) and !0 (not zero) work well for false and
true checking.

[Ben Pfaff]

Mark Odell <od*******@hotm ail.com> writes:

I have found that 0 (zero) and !0 (not zero) work well for false and
true checking.

I have found that 1 works well as !0.
--
Ben Pfaff
email: bl*@cs.stanford .edu
web: http://benpfaff.org

[Mark Odell]

Ben Pfaff wrote:

Mark Odell <od*******@hotm ail.com> writes:

I have found that 0 (zero) and !0 (not zero) work well for false and
true checking.

I have found that 1 works well as !0.

Yeah but that breaks my "no numbers except zero" rule. :-) Besides,
sometimes 1 looks like l (ell).

[JS]

I found this example:

#include <setjmp.h>
#include <stdio.h>

jmp_buf ex;

static int foo (int a, int b)
{
if (!b)
longjmp (ex, 1); /* THROW */
else
return a/b;
}

int main (void)
{
int x = 0, y = 1, z = 0;
if (setjmp (ex) == 0) /* TRY : longjmp branches back to here */
{
x = foo(y, z);
}
else /* CATCH */
{
printf ("Exception: attempt to divide by zero\n");
}
}

When foo is called after setjmp has been called, longjmp is called. Then
control jumps to setjmp but this time setjmp does not return 0 and
therefore: printf ("Exception: attempt to divide by zero\n"); is executed.

But I don't understand why setjmp don't return 0 after the longjmp call. Is
it because the second parameter to longjmp is used as the return value for
setjmp?

Or does the second paramter replace 0 in: if (setjmp (ex) == 0)?

[Martin Ambuhl]

JS wrote:

When setjmp is called how can the if statement evaluate to true or false
when setjmp only returns 0 or non-zero?

Since false is 0 and true is non-zero, I fail to see your problem.