Hi all,
Consider the following code:
#include<signal .h>
#include<stdio. h>
#include<sys/mman.h>
void handler(int sig)
{
printf("abhay: caught SIGSEGV\n\n");
}
void func(char *buffer)
{
unsigned int start=0;
//to make the starting address in mprotect as page aligned
asm("andl $-4096, %esp");
asm("movl %%esp, %0":"=r"(start) );
//raise(SIGSEGV);
printf("Mprotec t worked:
%d\n\n",mprotec t((void*)start, 4096,PROT_READ) );
buffer[3]='c';
printf("Mprotec t worked:
%d\n\n",mprotec t((void*)start, 4096,PROT_WRITE |PROT_READ|PROT _EXEC));
}
int main(void)
{
char buffer[10];
if( signal(SIGSEGV, handler)== SIG_ERR )
printf("problem installing new signal handler\n\n");
func(buffer);
printf("into main\n\n");
return 0;
}
My program makes the previous frame as write protected, thus when i am
in func() and i will try to write into the buffer that is allocated in
main(), it will generate SIGSEGV signal that is handled by my handler()
There is something wierd going on that i am not able to understand:
1. If both the mprotect functions are uncommented and i try to write
into the buffer[3]='c', SIGSEGV is generated
handler is called and it starts printing "abhay: caught SIGSEGV"
continuously on the screen until stack overflows. But it should have
printed it once and should have returned back into the func()
2. But if i comment both the mprotect and uncomment "raise(SIGSEGV) " to
generate the SIGSEGV signal explicitly, then this doesn't happen.
I am running the program on RedHat linux 8.0 and using GCC compiler.
Can anyone help me out?
Thanks. 5 2611
"Sontu" <ab******@gmail .com> wrote in message
news:11******** **************@ c13g2000cwb.goo glegroups.com.. . Hi all,
Consider the following code:
#include<signal .h> #include<stdio. h> #include<sys/mman.h>
Inclusion of a non-standard header file.
void handler(int sig) { printf("abhay: caught SIGSEGV\n\n"); }
Since when can you call printf from a signal handler?
Undefined behaviour!
<snipped the rest of the garbage>
This is all really off-topic for this newsgroup.
You want comp.unix.progr ammer
--
j
"Sontu" <ab******@gmail .com> wrote: Consider the following code:
#include<signal .h> #include<stdio. h> #include<sys/mman.h>
I'd rather not. This is quite off-topic.
//to make the starting address in mprotect as page aligned asm("andl $-4096, %esp"); asm("movl %%esp, %0":"=r"(start) );
And so is this (even worse, in fact)...
printf("Mprotec t worked: %d\n\n",mprotec t((void*)start, 4096,PROT_READ) );
....and this.
Note that calling printf() inside a signal handler causes undefined
behaviour.
As for the rest, I cannot tell whether you have a POSIX problem, a Unix
problem, a Linux problem, or a $Distro problem, so I can't tell you
where it _is_ on-topic - but it isn't here.
Richard
Sontu <ab******@gmail .com> wrote: Consider the following code:
#include<signal .h> #include<stdio. h> #include<sys/mman.h>
Non-standard header.
void handler(int sig) { printf("abhay: caught SIGSEGV\n\n"); }
You better don't use non-reentrant functions in signal handlers.
In principle not much more than setting a variable of type
sig_atomic_t is guaranteed to work in a signal handler.
void func(char *buffer) {
unsigned int start=0; //to make the starting address in mprotect as page aligned asm("andl $-4096, %esp"); asm("movl %%esp, %0":"=r"(start) );
No we get into completely platform dependent stuff. Don't expect
comments here in clc. Take that to a group that deals with the
platform you're using.
//raise(SIGSEGV);
printf("Mprotec t worked: %d\n\n",mprotec t((void*)start, 4096,PROT_READ) );
Non-standard function.
buffer[3]='c';
printf("Mprotec t worked: %d\n\n",mprotec t((void*)start, 4096,PROT_WRITE |PROT_READ|PROT _EXEC)); }
int main(void) { char buffer[10];
if( signal(SIGSEGV, handler)== SIG_ERR ) printf("problem installing new signal handler\n\n");
func(buffer);
printf("into main\n\n");
return 0; }
My program makes the previous frame as write protected, thus when i am
It may on the platform you are using, but that's nothing related to
the C language, which hasn't frames nor functions or to make them
write protected. Since you seem to be using Linux better take that
question to comp.os.linux.d evelopment.apps .
<OT>
Actually, when you get a real SIGSEGV signal, i.e. not one that you
faked using raise(), and don't exit() from the signal handler, flow
of control is passed back to instruction that led to the signal
getting raised. Since nothing has changed to remove the reason for
the signal it gets raised again immediately and you end up in an
infinite loop.
</OT>
Regards, Jens
--
\ Jens Thoms Toerring ___ Je***********@p hysik.fu-berlin.de
\______________ ____________ http://www.toerring.de
Sontu wrote: Consider the following code:
#include<signal .h> #include<stdio. h> #include<sys/mman.h>
No such header in Standard C, so we can't consider the code here.
.... snip ... unsigned int start=0; //to make the starting address in mprotect as page aligned asm("andl $-4096, %esp"); asm("movl %%esp, %0":"=r"(start) );
and these are syntax errors. 3rd strike. So you better look for a
newsgroup that deals with your particular system and compiler.
--
"If you want to post a followup via groups.google.c om, don't use
the broken "Reply" link at the bottom of the article. Click on
"show options" at the top of the article, then click on the
"Reply" at the bottom of the article headers." - Keith Thompson
I am sorry for troubling you people. I will try to do what some of you
have suggested and if the problem persists, i will post it to another
group comp.unix.progr ammers.
Thanks a lot for giving your time.
Abhay This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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