scanf to include white spaces

[Jonathan Ng]

Hi,

I was wondering if there was a way to include the white spaces in a string.

Currently, I am using:
scanf("%s", &input);

However, this doesn't include the 'space' character or any other white
spaces. Is there a way I can include the 'space' character rather than skip
in.

Thanks in advance.

[Michael Mair]

Hiho,

I was wondering if there was a way to include the white spaces in a string.

Currently, I am using:
scanf("%s", &input);

However, this doesn't include the 'space' character or any other white
spaces. Is there a way I can include the 'space' character rather than skip
in.
Yep. Use a list of permitted/prohibited characters.
Example:
cat scanblank.c #include <stdio.h>

int main(void)
{
char string[80];

puts("first test. Enter string: ");
scanf("%[^\t\n]",string);
puts(string);
while(getchar() !=(int)'\n');

puts("\nsecond test. Enter string: ");
scanf("%[ a-zA-Z0-9+*/-]",string);
puts(string);

return 0;
}
./scanblank first test. Enter string:
hello, world !
hello, world

second test. Enter string:
abcde j, fghk
abcde j

In the first test, we scan for everything with exception of '\t' and
'\n'. Between d and !, I entered a tabulator. In the second test, we
scan for
a,b,c,..,z,A,B, C,..,Z,0,1,2,.. ,9,+,*,/,-
You always read at least one of the permitted/non-prohibited characters.
The hyphen inbetween marks a range rather than meaning the hyphen
character. The list must be nonempty.
To scan (or scan not) for ], you have to put it immediately after [ or
[^, respectively.

Remark: I am not checking the return values of puts and scanf.
Especially the latter might be necessary for you.
Cheers
Michael

[Jens.Toerring]

Jonathan Ng <jo****@hotmail .com> wrote:

I was wondering if there was a way to include the white spaces in a string. Currently, I am using:
scanf("%s", &input);
This looks rather strange. When you have a '%s' format specifier the
variable must be an array pointer. And if 'input' is one than you
would need

scanf( "%s", input );

And I have problems to imagine a situation where 'input' could be
anything else than an array.
However, this doesn't include the 'space' character or any other white
spaces. Is there a way I can include the 'space' character rather than skip
in.

No, scanf() stops at white space. And I would guess that you would be
a lot better of using fgets() here. First of all, when using scanf()
you have no way to check that the string the user enters isn't longer
than there is place in your 'input' array - if that happens scanf()
will happily write beyond the end of the array with impossible to
forsee consequences (including everything to seem to work nicely).
And then you get a whole line of input (or as many characters as fit
into the buffer) and you than can split it up however you need and
aren't handicapped by the limitations of scanf().

Regards, Jens
--
\ Jens Thoms Toerring ___ Je***********@p hysik.fu-berlin.de
\______________ ____________ http://www.toerring.de

[Emmanuel Delahaye]

Jonathan Ng wrote on 12/08/04 :

Hi,

I was wondering if there was a way to include the white spaces in a string.

Currently, I am using:
scanf("%s", &input);
This '&' is suspicious. How is 'input' defined?
However, this doesn't include the 'space' character or any other white
spaces. Is there a way I can include the 'space' character rather than skip
in.

For many reasons (including your issue), it's better to get a line from
the user with fgets(). BTW, it's a FAQ.

--
Emmanuel
The C-FAQ: http://www.eskimo.com/~scs/C-faq/faq.html

"C is a sharp tool"

[pete]

Jonathan Ng wrote:

Hi,

I was wondering if there was a way to include the white spaces in a string.

Currently, I am using:
scanf("%s", &input);

However, this doesn't include the 'space' character or any other white
spaces.
Is there a way I can include the 'space' character rather than skip
in.

/* You can use Pop's Device. */

#include <stdio.h>
#include <stdlib.h>

#define LENGTH 65
#define str(x) # x
#define xstr(x) str(x)

int main(void)
{
int rc;
char array[LENGTH + 1] = "";

fputs("Enter a string with spaces:", stdout);
fflush(stdout);
rc = scanf("%" xstr(LENGTH) "[^\n]%*[^\n]", array);
if (!feof(stdin)) {
getchar();
}
while (rc == 1) {
printf("Your string is: \n%s\n", array);
fputs("Hit Enter key to end, or enter "
"a string with spaces:", stdout);
fflush(stdout);
rc = scanf("%" xstr(LENGTH) "[^\n]%*[^\n]", array);
if (!feof(stdin)) {
getchar();
}
}
return 0;
}

--
pete

[Dan Pop]

In <mn************ ***********@YOU RBRAnoos.fr> Emmanuel Delahaye <em***@YOURBRAn oos.fr> writes:

Jonathan Ng wrote on 12/08/04 :

Hi,

I was wondering if there was a way to include the white spaces in a string.

Currently, I am using:
scanf("%s", &input);

This '&' is suspicious. How is 'input' defined?

However, this doesn't include the 'space' character or any other white
spaces. Is there a way I can include the 'space' character rather than skip
in.

For many reasons (including your issue), it's better to get a line from
the user with fgets(). BTW, it's a FAQ.

Pray tell, why is fgets() better than scanf for the OP's issue?

As a matter of fact and excepting gets(), fgets() is *always* the
worst solution, when bullet proof behaviour is desired/need.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de