Sizeof and increment operators

[Anjali M]

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}
The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

Thanks,
Anjali.

[Joona I Palaste]

Charles Richmond <ri******@plano .net> scribbled the following:

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

You are incredibly rude. What makes you so sure the OP sucked a job from
the US? What makes you so sure the OP has a job as a programmer at all?
This might just as well be a question from a genuine C newbie. And
besides, even if he did suck up the job from the US, what business is
that of yours? This is a technical newsgroup. If you need to vent your
patriotism, go to a politics newsgroup.

--
/-- Joona Palaste (pa*****@cc.hel sinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"You could take his life and..."
- Mirja Tolsa

[Nitin Bhardwaj]

>Charles Richmond <ri******@plano .net> wrote in message >news:<40****** *********@plano .net>...

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

It seems frm yr language that u hate Indians !!

Did u lost ur job to an Indian, buddy?

Cough up yr technical skills to match-up to ours & take on the
competition instead of making political transgressions on a technical
group like c.l.c!!

[Richard Bos]

ni************* @hotmail.com (Nitin Bhardwaj) wrote:

Charles Richmond <ri******@plano .net> wrote in message >news:<40****** *********@plano .net>...

suck it up from the U. S.???

It seems frm yr language that u hate Indians !!

Did u lost ur job to an Indian, buddy?

Cough up yr technical skills to match-up to ours & take on the
competition instead of making political transgressions on a technical
group like c.l.c!!

Ow! I know the English did some pretty awful things in India, but do you
_have_ to take revenge by murdering their language? Leave that to the
USAnians, like Mr. Richmond ;->

Richard

[Dan Pop]

In <40************ ***@plano.net> Charles Richmond <ri******@plano .net> writes:

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

How many job assignments like this have you seen? This is not only
a newbie question, it is a perfectly legitimate newbie question.

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.

[Anjali M]

Charles Richmond <ri******@plano .net> wrote in message news:<40******* ********@plano. net>...

Anjali M wrote:

#include <stdio.h>

int main()
{
int number = 10;
printf("Number is: %d\n", number);

printf("Sizeof of number is: %d\n", sizeof(number++ ));

printf("Number now is: %d\n", number);

return 0;
}

The post-increment operator doesnt seem to work here. The value of the
number remains the same even after the call to the sizeof operator.
Can someone clarify this please?

What's the matter??? Can't you *do* the job after you
suck it up from the U. S.???

I don't know what you have got against me. I asked a very valid
question on this newsgroup and I _dont_ have to take this crap from
you. If you can be rude, so can _I_. So, better be careful before you
say something like this again.